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victus00 [196]
2 years ago
12

Refer to the image i couldnt copy it so the image is the quesstion answer in true or false

Mathematics
1 answer:
Irina18 [472]2 years ago
6 0

The sign of "b" on the numerator should be negative. So we conclude that the correct option is false.

<h3>Is the equation in the image correct or incorrect?</h3>

For a quadratic equation of the form:

y = a*x^2 + b*x + c

By using the Bhaskara's formula, the solutions of the equation:

0 = a*x^2 + b*x + c

Are given by the formula:

x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a}

Notice that the sign of the first term on the numerator should be negative, while on the image it is positive.

So the equation shown in the image is incorrect.

If you want to learn more about quadratic equations:

brainly.com/question/1214333

#SPJ1

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List the following in order from least to greatest<br><br> -3/5, -0.4, -1, -0.5
nikklg [1K]

-1

- 3/5

- 0.5

-0.4

The least is always the one furthest away from 0

5 0
3 years ago
I NEED HELP PLEASE, THANKS! :) Determine the zeros for and the end behavior of f(x) = x(x – 4)(x + 2)^4.
Amiraneli [1.4K]

Answer:  a) zeros: x = {0, 4, -2}

               b) as x → ∞,  y → ∞

                   as x → -∞,  y → ∞

<u>Step-by-step explanation:</u>

I think you mean (a) find the zeros and (b) describe the end behavior

(a) Find the zeros by setting each factor equal to zero and solving for x:

      x (x - 4) (x + 2)⁴ = 0

  • x = 0   Multiplicity of 1  --> odd multiplicity so it crosses the x-axis
  • x = 4  Multiplicity of 1  --> odd multiplicity so it crosses the x-axis
  • x = -2 <u>Multiplicity of 4 </u> --> even multiplicity so it touches the x-axis

                       Degree  =  6

(b) End behavior is determined by the following two criteria:

  1. Sign of Leading Coefficient (Right side): Positive is ↑, Negative is ↓
  2. Degree (Left side): Even is same direction as right side, Odd is opposite direction of right side

Sign of the leading coefficient is Positive so right side goes UP

                                                                        as x → ∞,  y → ∞

Degree of 6 is Even so Left side is the same direction as right (UP)

                                                                        as x → -∞,  y → ∞

7 0
3 years ago
Select all expressions less than 5-square root of 135
belka [17]
It should be b im not sure


5 0
3 years ago
The perimeter of a rectangular field is 364 yards. If the width of the field is 84 yards, what is its length?
elena55 [62]

The perimeter of a rectangular field is 364 yards. If the width of the field is 84 yards, what is its length?


(364 : 2) - 84 =

182 - 84 =

98



3 0
3 years ago
Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74
lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0
3 years ago
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