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victus00 [196]
2 years ago
12

Refer to the image i couldnt copy it so the image is the quesstion answer in true or false

Mathematics
1 answer:
Irina18 [472]2 years ago
6 0

The sign of "b" on the numerator should be negative. So we conclude that the correct option is false.

<h3>Is the equation in the image correct or incorrect?</h3>

For a quadratic equation of the form:

y = a*x^2 + b*x + c

By using the Bhaskara's formula, the solutions of the equation:

0 = a*x^2 + b*x + c

Are given by the formula:

x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a}

Notice that the sign of the first term on the numerator should be negative, while on the image it is positive.

So the equation shown in the image is incorrect.

If you want to learn more about quadratic equations:

brainly.com/question/1214333

#SPJ1

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marissa [1.9K]

Answer:

B

Step-by-step explanation:

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we get 3/(5m)

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8 0
3 years ago
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Veronika [31]

Answer:

m=2/3

Step by Step Explanation:

x1,y1= 3,-6

x2,y2=3,-3

m={-3-3}           (Fraction Form)

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3 years ago
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lilavasa [31]

Answer:

y = -13x + 55

Step-by-step explanation:

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y = -13x + 4

now we take the grafient of the equation which is 13 :

m × 13 = -1

m = -13

so now we hv a new gradient then we can find the equation use the formula y = mx + c :

m = -13 point = ( 4 , 3 )

sub them into the formula,

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3 = -52 + c

3 + 52 = c

55 = c

c = 55

now we rewrite again the c and the m to become a complete equation : y = -13x + 55

5 0
3 years ago
√2 times √800 anyone know?
jeka94

\sqrt{2}  \times  \sqrt{800}

\sqrt{2}  \times 20 \sqrt{2}

\sqrt{2}  \times  \sqrt{2}  =  \sqrt{4}  \:  = 2

20 \times 2 = 40

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The answer is c: x=5
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