Using slope-intercept form, y = mx + b where m = slope and b = y-intercept:
We know our slope is -6. This can be interpreted as -6/1, which rise-over-run-wise, means that when y changes by 6, x changes inversely by 1.
To find that y-intercept, though, we need to find the value of y when x = 0.
Use our point (-9, -3) to find this...
We want to add 9 to x so that it becomes 0.
According to our slope, this means subtracting 54 from y.
Our y-intercept is at (0, -57), with -57 being the value of b we put in our equation.

You could also just use point-slope form:
y - y¹ = m(x - x¹)
y - (-3) = -6(x - (-9))
y + 3 = -6(x + 9)
And convert to slope-intercept if you want:
y + 3 = -6x - 54
y = -6x - 57
Can you please add a picture of the problem or type all the measurements and information?
Answer/Step-by-step explanation:
Given,
10x - 3y = 3
3x + 10y = 30
Rewrite both equation in slope-intercept form, y = mx + b.
Where, m = slope of the line.
Thus,
✔️10x - 3y = 3
-3y = -10x + 3
y = 10/3x - 1
Slope of this line would be 10/3
✔️3x + 10y = 30
10y = -3x + 30
y = -3/10x + 3
The slope of this line is -³/10.
✔️The two lines are pendivukar to each other because the slope of one is the negative reciprocal of the other.