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Verdich [7]
3 years ago
5

3

Mathematics
1 answer:
nikitadnepr [17]3 years ago
3 0

Answer:

y = (1/4)x - 3

Step-by-step explanation:

The slope-intercept form is y = mx + b.  Here we are told that the line passes through (-8, -5) and that its slope is 1/4 (is that correct?).  

Substituting -5 for y, -8 for x and 1/4 for m, we get an equation for the y-intercept, b:

-5 = (1/4)(-8) + b, or

-5 = -2 + b, so b = -3, and the desired equation is

y = (1/4)x - 3

You might be interested in
What is the sum of 2/11’ 2/7’ and 1/11’?
pav-90 [236]
Solution

To solve this addition of fractions we are gonna apply the fraction rule which is;

a/c + b/c = (a + b)/c

2/11 + 1/11 = (2 + 1)/11


= (2 + 1)/11 + 2/7

Now add the numerators 2 + 1

= (2 + 1)/11 + 2/7

= 3/11 + 2/7

Now we find the least common multiple

The least common multiple of 11 and 7 is 77.

But before that we cross multiply the numerators.

3 * 7 = 21
2 * 11 = 22

Now the ajustes fraction is;

21/77 + 22/77


Apply the fraction rule which is;

a/c + b/c = (a + b)/c

= (21 + 22)/77

Now we add the numerators.

43/77

Therefore the answer in fraction is 43/77 and in decimal form it is 0.55841
6 0
3 years ago
8th grade math urgent need help
Rainbow [258]

Answer:

p > 4

Step-by-step explanation:

your welcome

7 0
3 years ago
Read 2 more answers
In a teacher's math course, a linear regression line was calculated to predict
Marat540 [252]

The given equation is the best line that approximates the linear

relationship between the midterm score and the score in the final exam.

  • AJ's residual is 0.3, which is not among the given options, therefore, the correct option is. <u>E. None of these</u>.

Reasons:

The given linear regression line equation is; \hat y = 25.5 + 0.82·\mathbf{\hat x}

Where;

\hat y = Final exam score;

\hat x = The midterm score;

AJ score in the first test, \hat x = 90

AJ's actual score in the exam = 99

Required:

The value of AJ's residual

Solution:

By using the regression line equation, we have;

The predicted exam score, \hat y = 25.5 + 0.82 × 90 = 99.3

  • The residual score = Predicted score - Actual score

∴ AJ's residual = 99.3 - 99 = 0.3

AJ's residual = 0.3

Therefore, the correct option is option E;

  • <u>E. None of these</u>

Learn more about regression line equation here:

brainly.com/question/9339658

brainly.com/question/7361586

brainly.com/question/14747095

6 0
3 years ago
6y-5=11 what the answer I’m having a hard time finding it
QveST [7]

6y-5=11

Move -5 to the other side. Sign changes from -5 to +5.

6y-5+5=11+5

6y=11+5

6y=16

Divide by 6 for both sides to get y by itself.

6y/6=16/6

Cross out 6 and 6, divide by 6 and then becomes 1*1*y=y

y=16/6

Reduce 16/6 by dividing by 2

16/2=8

6/2=3

Answer: y=8/3 or y=2 2/3

6 0
3 years ago
Read 2 more answers
Before every​ flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the ai
ollegr [7]

Answer:

The probability that the aircraft  is  overload = 0.9999

Yes , The pilot has to be take strict action .

Step-by-step explanation:

P.S - The exact question is -

Given - Before every​ flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 37 ​passengers, and a flight has fuel and baggage that allows for a total passenger load of 6,216 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6216/37 = 168 lb. Assume that weight of men are normally distributed with a mean of 182.7 lb and a standard deviation of 39.6.

To find - What is the probability that the aircraft is​ overloaded ?

         Should the pilot take any action to correct for an overloaded aircraft ?

Proof -

Given that,

Mean, μ = 182.7

Standard Deviation, σ = 39.6

Now,

Let X be the Weight of the men

Now,

Probability that the aircraft is loaded be

P(X > 168 ) = P(\frac{x - \mu}{\sigma} > \frac{168 - \mu}{\sigma} )

                 = P( z > \frac{168 - 182.7}{39.6} )

                 = P( z > -0.371)

                 = 1 - P ( z ≤ -0.371 )

                 = 1 - P( z > 0.371)

                 = 1 - 0.00010363

                 = 0.9999

⇒P(X > 168) = 0.9999

As the probability of weight overload = 0.9999

So, The pilot has to be take strict action .

5 0
3 years ago
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