The intersection of the two equations is (1, 1/5). Since the question is asking for the value of x, x = 1.
<span>We want to check how many intersections line A and B have, that is, we want to check how many common solutions do these equations have:
</span>
i) 2x + 2y = 8
ii) x + y = 4
<span>
use equation ii) to write y in terms of x as : y=4-x,
substitute y =4-x in equation i):
</span>2x + 2y = 8
2x + 2(4-x) = 8
<span>2x+8-2x=8
8=8
this is always true, which means the equations have infinitely many common solutions.
Answer: </span><span>There are infinitely many solutions.</span><span>
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Answer:
D
Step-by-step explanation:
If it intersects the x axis, then y = 0. This is not possible, as you can plug in x to be 1/100000000000000000000000000000000000, or something very tiny, but it will never get 0. So, A is not a choice.
This also means B is not a choice.
If C is a choice, then it does not intercept the y axis, or x cannot be 0. This is not true, because (0, 1) is on the graph.
Finally, we have D. It intercepts the y axis (we have proven this in C). So, this is the only answer choice that is correct.
Since A‘(-1,1) is on the line y=-x, reflecting it about the line doesn't change its coordinate, so A's coordinate is (-1,1). Reflecting B'(-2,1) about y=-x switches both the sign and the number of x and y, so B=(-1,2), and C'(-1,0) becomes C(0,1). Drawing out the graph with the points and the line helps.
Answer:
3 • (2xy - 7) • (xy + 2)
Step-by-step explanation:
(((2•3x2) • y2) - 9xy) - 42
6x2y2 - 9xy - 42 = 3 • (2x2y2 - 3xy - 14)
