1 answer:
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The given equation is the best line that approximates the linear
relationship between the midterm score and the score in the final exam.
- AJ's residual is 0.3, which is not among the given options, therefore, the correct option is. <u>E. None of these</u>.
Reasons:
The given linear regression line equation is; = 25.5 + 0.82·
Where;
= Final exam score;
= The midterm score;
AJ score in the first test, = 90
AJ's actual score in the exam = 99
Required:
The value of AJ's residual
Solution:
By using the regression line equation, we have;
The predicted exam score, = 25.5 + 0.82 × 90 = 99.3
- The residual score = Predicted score - Actual score
∴ AJ's residual = 99.3 - 99 = 0.3
AJ's residual = 0.3
Therefore, the correct option is option E;
- <u>E. None of these</u>
Learn more about regression line equation here:
Answer:
The probability that the aircraft is overload = 0.9999
Yes , The pilot has to be take strict action .
Step-by-step explanation:
P.S - The exact question is -
Given - Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 37 passengers, and a flight has fuel and baggage that allows for a total passenger load of 6,216 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6216/37 = 168 lb. Assume that weight of men are normally distributed with a mean of 182.7 lb and a standard deviation of 39.6.
To find - What is the probability that the aircraft is overloaded ?
Should the pilot take any action to correct for an overloaded aircraft ?
Proof -
Given that,
Mean, μ = 182.7
Standard Deviation, σ = 39.6
Now,
Let X be the Weight of the men
Now,
Probability that the aircraft is loaded be
P(X > 168 ) = P( )
= P( z > )
= P( z > -0.371)
= 1 - P ( z ≤ -0.371 )
= 1 - P( z > 0.371)
= 1 - 0.00010363
= 0.9999
⇒P(X > 168) = 0.9999
As the probability of weight overload = 0.9999
So, The pilot has to be take strict action .
