Question

write the standard form of the equation of the circle with radius and center (h,k). r =4; (h,k) = (-2,-3) nee help please answer.

Answer 1

The equation of the circle is written as (x-h)² + (y-k)² = r²

With the given center and radius the equation will be 

(x + 2)² + (y + 3)² = 16

The answer is A

Hope this helps :)

Answer 2

The standard form of the circle equation is:
${(x - h)}^{2} + {(y - k)}^{2} = {r}^{2}$
In this problem,
r = 4
h = -2
k = -3

Therefore, we just plug in the numbers and simplify:
${(x - ( - 2))}^{2} + {(y - ( - 3))}^{2} = {(4)}^{2} \\ {(x + 2)}^{2} + {(y + 3)}^{2} = 16$
The correct answer is A