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Vera_Pavlovna [14]
4 years ago
11

Please help, find the shaded portion of the circle’s area.

Mathematics
2 answers:
Nookie1986 [14]4 years ago
7 0

The area of the shaded portion is approximately 25.6 cm

sdas [7]4 years ago
4 0

The shaded portion is 7.3

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A bicycle is traveling at 16 miles per hour. How many feet will it cover in 35 seconds? Round your answer to the nearest tenth o
ch4aika [34]

A  bicycle is traveling at 16 miles per hour it covers 821.33 ft in 35 seconds.

It is required to find How many feet will it cover in 35 seconds.

<h3>What is conversion?</h3>

conversion is the process of changing the value of one form to another for example inches to millimeters, or liters to gallons. Units are used for measuring length, measuring weight, measuring capacity, measuring temperature, and measuring speed.

Given that:

1 hour = 60min×60sec = 3600 sec

1 miles = 5280 feet

16 miles = 16×5280ft = 84480 ft

3600sec ................. 84480  ft

35sec ................................ x ft

x = 35×84480/3600

=2956800 /3600

= 821.33 feet.

Hence, a bicycle is traveling at 16 miles per hour it covers 821.33 ft in 35 seconds.

Learn more about conversion here:

brainly.com/question/3477680

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2 years ago
ASAP <br> HELP<br> NEEDED<br> WITH<br> THIS<br> QUESTION
dalvyx [7]

Answer:

EF is the best vector described to intersect both point s

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3 years ago
• Abe is afraid of water.<br> • Brenda does not like to read or swim,<br> Who is the painter?
pashok25 [27]

Answer:

Abe

Step-by-step explanation:

When it comes to art, you may need to read books in order to understand how to paint. That is as logical I can get :)

7 0
3 years ago
Read 2 more answers
PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS PLS ASAP PLS PLS HELP ASAP THANKS
Ipatiy [6.2K]

Answer:

I believe the answer is B. 15/5 = n/12

Step-by-step explanation:

Once again same method as I've explained before. However, this one tricked me a little bit and still is because of the appearance of the smaller triangle. However, If I don't focus on that I believe this answer is correct. This is because in order to find the missing side we need to find the factor of which the triangle was expanded. So we must divide a given side of the bigger triangle by the same similar side of the little triangle, like 15/5. Then we must divide n by its similar side which the appearance made me think 13 which is not an option so I believe it is 12 and it was just trying to throw me off. So n/12. Therefore that is why I believe B is correct.

7 0
2 years ago
During halftime of a basketball ​game, a sling shot launches​ T-shirts at the crowd. A​ T-shirt is launched from a height of 4 f
Sonbull [250]

Answer:

(a) The time the T-shirt takes to maximum height is 2 seconds

(b) The maximum height is 68 ft

(c) The range of the function that models the height of the T-shirt over time given above is 4 + 64\cdot t - 16 \cdot  t^{2}

Step-by-step explanation:

Here, we note that the general equation representing the height of the T-shirt as a function of time is

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

Where:

h = Height reached by T-shirt

t = Time of flight

u = Initial velocity = 64 ft/s

g = Acceleration due to gravity (negative because upward against gravity) = 32 ft/s²

h₁ = Initial height of T-shirt = 4 ft

(a) The maximum height can be found from the time to maximum height given as

v = u - gt

Where:

u = Initial velocity = 64 ft/s

v = Final upward velocity at maximum height = 0 m/s

g = 32 ft/s²

Therefore,

0 = 64 - 32·t

32·t = 64 and

t = 64/32 = 2 seconds

(b) Therefore, maximum height is then

h = 4 + 64\times 2 - \frac{1}{2} \times 32  \times  2^{2}

∴ h = 68 ft

The T-shirt is then caught 41 ft above the court on its way down

(c) The range of the function that models the height of the T-shirt over time given above is derived as

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

With u = 64 ft/s

g = 32 ft/s² and

h₁ = 4 ft

The equation becomes

h =4 + 64\cdot t - \frac{1}{2} \times 32  \cdot  t^{2} = 4 + 64\cdot t - 16 \cdot  t^{2}.

6 0
3 years ago
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