4 years ago

Subtract four-fifths from 8 times b

Mathematics

1 answer:

mote1985 [20]4 years ago

4 0

What does b = 4/5 8b?

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Sketch the equilibrium solutions for the following DE and use them to determine the behavior of the solutions.

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Answer:

$y=\dfrac{1}{1-Ke^{-t}}$

Step-by-step explanation:

Given

The given equation is a differential equation

$\dfrac{dy}{dt}=y-y^2$

$\dfrac{dy}{dt}=-(y^2-y)$

By separating variable

⇒ $\dfrac{dy}{(y^2-y)}=-t$

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Now by taking integration both side

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$\dfrac{y-1}{y}=e^{-t+c}$

$\dfrac{y-1}{y}=Ke^{-t}$

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from above equation we can say that

When t will increases in positive direction then $e^{-t}$ will decreases it means that ${1-Ke^{-t}}$ will increases, so y will decreases. Similarly in the case of negative t.

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Convert 62F to Celsius. Round to the nearest degree.

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