Step-by-step explanation:
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Answer:
The probability that the page will get at least one hit during any given minute is 0.9093.
Step-by-step explanation:
Let <em>X</em> = number of hits a web page receives per minute.
The random variable <em>X</em> follows a Poisson distribution with parameter,
<em>λ</em> = 2.4.
The probability function of a Poisson distribution is:
![P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...](https://tex.z-dn.net/?f=P%28X%3Dx%29%3D%5Cfrac%7Be%5E%7B-%5Clambda%7D%5Clambda%5E%7Bx%7D%7D%7Bx%21%7D%3B%5C%20x%3D0%2C1%2C2%2C...)
Compute the probability that the page will get at least one hit during any given minute as follows:
P (X ≥ 1) = 1 - P (X < 1)
= 1 - P (X = 0)
![=1-\frac{e^{-2.4}(2.4)^{0}}{0!}\\=1-\frac{0.09072\times1}{1} \\=1-0.09072\\=0.90928\\\approx0.9093](https://tex.z-dn.net/?f=%3D1-%5Cfrac%7Be%5E%7B-2.4%7D%282.4%29%5E%7B0%7D%7D%7B0%21%7D%5C%5C%3D1-%5Cfrac%7B0.09072%5Ctimes1%7D%7B1%7D%20%5C%5C%3D1-0.09072%5C%5C%3D0.90928%5C%5C%5Capprox0.9093)
Thus, the probability that the page will get at least one hit during any given minute is 0.9093.
Answer:
21/4 or 5.25
Step-by-step explanation:
Answer and explanation:
- 5 = b - 2.3 add 2.3 to both sides
+2.3 +2.3
- 2.7 = b