Answer:
P is exactly 3km east from the oil refinery.
Step-by-step explanation:
Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:
![\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}](https://tex.z-dn.net/?f=%5Csqrt%7B%283%20-%20d%29%5E2%20%2B%202%5E2%7D%20%3D%20%5Csqrt%7B%283%20-%20d%29%5E2%20%2B%204%7D)
So the cost of laying pipe under water with this distance is
![800000\sqrt{(3 - d)^2 + 4}](https://tex.z-dn.net/?f=800000%5Csqrt%7B%283%20-%20d%29%5E2%20%2B%204%7D)
And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:
![800000\sqrt{(3 - d)^2 + 4} + 400000d](https://tex.z-dn.net/?f=800000%5Csqrt%7B%283%20-%20d%29%5E2%20%2B%204%7D%20%2B%20400000d)
We can find the minimum value of this by taking the 1st derivative and set it to 0
![800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0](https://tex.z-dn.net/?f=800000%5Cfrac%7B2%2A0.5%2A%283-d%29%28-1%29%7D%7B%5Csqrt%7B%283%20-%20d%29%5E2%20%2B%204%7D%7D%20%2B%20400000%20%3D%200)
We can move the first term over to the right hand side and divide both sides by 400000
![1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}](https://tex.z-dn.net/?f=1%20%3D%202%5Cfrac%7B3%20-%20d%7D%7B%5Csqrt%7B%283%20-%20d%29%5E2%20%2B%204%7D%7D)
![\sqrt{(3 - d)^2 + 4} = 6 - 2d](https://tex.z-dn.net/?f=%5Csqrt%7B%283%20-%20d%29%5E2%20%2B%204%7D%20%3D%206%20-%202d)
From here we can square up both sides
![(3 - d)^2 + 4 = (6 - 2d)^2](https://tex.z-dn.net/?f=%283%20-%20d%29%5E2%20%2B%204%20%3D%20%286%20-%202d%29%5E2)
![9 - 6d + d^2 + 4 = 36 - 24d + 4d^2](https://tex.z-dn.net/?f=9%20-%206d%20%2B%20d%5E2%20%2B%204%20%3D%2036%20-%2024d%20%2B%204d%5E2)
![3d^2-18d+27 = 0](https://tex.z-dn.net/?f=3d%5E2-18d%2B27%20%3D%200)
![d^2 - 6d + 9 = 0](https://tex.z-dn.net/?f=d%5E2%20-%206d%20%2B%209%20%3D%200)
![(d - 3)^2 = 0](https://tex.z-dn.net/?f=%28d%20-%203%29%5E2%20%3D%200)
![d -3 = 0](https://tex.z-dn.net/?f=d%20-3%20%3D%200)
d = 3
So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.
Because ABCD is a rhombus, ΔABC ~ ΔADC.
The length of AC = 4 (the base of ΔABC.
The height of ΔABC = 7 - 1 = 6
The area of ΔABC is
(1/2)*4*6 = 12
Therefore the area of ABCD = 2*12 = 24
Answer: 24
Answer:
-3
Step-by-step explanation:
-1 -2 = -3
In this problem, you would just divide your test results by the maximum test points you can get.
60 divided by 75 is 0.8, which is 80%, which is probably a grade I will never see in my life :P
Hope I helped!
I'm not super good at triangles, but I think it would be 20 yd^2, but I'm sorry I'm not totally sure