The answer is going to be
X=20
Answer:
A = (2p + 9) (2p - 9)
B = (x - 9) (x - 4)
Step-by-step explanation:
For A : Rewrite 4p^2 as (2p)^2.
(2p)^2−81
Rewrite 81 as 9^2.
(2p)^2−9^2
Since both terms are perfect squares, factor using the difference of squares formula, a^2 − b^2 = ( a + b ) ( a − b ) where a = 2p and b = 9 .
(2p + 9) (2p − 9)
For B : Consider the form x^2 + bx + c . Find a pair of integers whose product is c and whose sum is b . In this case, whose product is 36 and whose sum is − 13 .
-9, -4
(x - 9) (x - 4)
I hope this helps.
1st number = n
2nd number = n+1
3rd number = n+2
sum of the squares of 3 consecutive numbers is 116
n² + (n+1)² + (n+2)² = 116
n² + (n+1)(n+1) + (n+2)(n+2) = 116
n² + [n(n+1)+1(n+1)] + [n(n+2)+2(n+2)] = 116
n² + n² + n + n + 1 + n² + 2n + 2n + 4 = 116
n² + n² + n² + n + n + 2n + 2n + 1 + 4 = 116
3n² + 6n + 5 = 116 Last option.
Any with an odd number of minus signs.
Perhaps the 1st and 4th, if I read it right.
Answer:
No idea
Step-by-step explanation:
