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Anna007 [38]
4 years ago
15

If

x-formula"> and y < 0 ,where is the point (x,y) located?
a) quadrant I
b) quadrant II
c) quadrant III
d) quadrant IV​
Mathematics
2 answers:
Dmitry_Shevchenko [17]4 years ago
7 0

Answer:

Quadrant III

Step-by-step explanation:

x < 0 is the area to the left of the y-axis, and y < 0 is the area beneath the x-axis.  This point is therefore located in Quadrant III.

miss Akunina [59]4 years ago
5 0

Answer:

c) quadrant III

Step-by-step explanation:

I will be quick in this question:

\text {For }y

\text {For }x

What both have in common?

So, the answer is <u>Quadrant III</u><u>.</u>

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Ipatiy [6.2K]

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Step-by-step explanation:

100 - x = 38

x =62

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Part C of Jim and his dad are building a rectangular flower bed.
charle [14.2K]
I gotchu

The perimeter is 35. If we were to change the width, which is one of the dimensions of the flower bed, The perimeter will change. This means that perimeter will no longer be 35. So in order to keep the perimeter as it is, if we change one dimension, we must also change the other.

Let's solve for the length, using the formula to see how much the length changes from.

p = 2l + 2w

35 = 2l + 2(15)

35 = 2l + 30

5 = 2l

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We must increase the length from 2.5 feet. This is because decreasing one dimension will decrease the perimeter. But if we increase the other dimension as well, it will restore the perimeter to where is was initially.
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Question 6: please help me out here :(((
Murljashka [212]

Answer:

m∠1 = 106

Step-by-step explanation:

Given: m∠5 = 106

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The Alternate Interior Angles Theorem states that, when two parallel lines are cut by a transversal , the resulting alternate interior angles are congruent.

Therefore: m∠1 = 106

7 0
3 years ago
Use calculus to find the largest possible area for a rectangular field that can be enclosed with a fence that is 500 meters long
rewona [7]
Let x and y be the sides of the rectangle. The perimeter is given to be 500m, so we are maximizing the area function A(x,y)=xy subject to the constraint 2x+2y=500.

From the constraint, we find

2x+2y=500\implies x+y=250\implies y=250-x

so we can write the area function independently of y:

A(x,y)=\hat A(x)=x(250-x)=250x-x^2

Differentiating and setting equal to zero, we find one critical point:

\dfrac{\mathrm d\hat A(x)}{\mathrm dx}=250-2x=0\implies x=125

which means y=250-125=125, so in fact the largest area is achieved with a square fence that surrounds an area of A(125,125)=125^2=15625\text{ m}^2.
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3 years ago
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Nata [24]

Answer:

21

Step-by-step explanation:

84000/4000=84/4=21

4 0
3 years ago
Read 2 more answers
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