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tigry1 [53]
3 years ago
8

Which pay rates are common ways employers pay employees?

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
4 0

Answer:

Commission

Hourly pay

sometimes quarterly pay depending on the commission pay policy

Tju [1.3M]3 years ago
3 0

Answer:

i can not pike all

Step-by-step explanation:

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Determine which situation(s) best describes operations with the numbers 4.58 and -0.145. Select all situations that apply.
saul85 [17]

Answer:

Real Numbers: Any number that can name a position on a number line is a real number. Every position on a number line can be named by a real number in some form.

An important property of real numbers is the Density Property. It says that between any two real numbers, there is always another real number.

Rational Numbers: Any number that can be written in fraction form is a rational number. This includes integers, terminating decimals, and repeating decimals as well as fractions.

An integer can be written as a fraction simply by giving it a denominator of one, so any integer is a rational number.

;  ;  

A terminating decimal can be written as a fraction simply by writing it the way you say it: 3.75 = three and seventy-five hundredths = , then adding if needed to produce a fraction: . So, any terminating decimal is a rational number.

A repeating decimal can be written as a fraction using algebraic methods, so any repeating decimal is a rational number.

Integers: The counting numbers (1, 2, 3, ...), their opposites (negative1, negative2, negative3, ...), and zero are integers. A common error for students in grade 7 is to assume that the integers account for all (or only) negative numbers.

Whole Numbers: Zero and the positive integers are the whole numbers.

Natural Numbers: Also called the counting numbers, this set includes all of the whole numbers except zero (1, 2, 3, ....)

Irrational Numbers: Any real number that cannot be written in fraction form is an irrational number. These numbers include the non-terminating, non-repeating decimals (pi, 0.45445544455544445555..., 2, etc.). Any square root that is not a perfect root is an irrational number. For example, 1 and 4 are rational because 1 = 1 and 4 = 2, but 2 and 3 are irrational-there are no perfect squares between 1 and 4. All four of these numbers do name points on the number line, but they cannot be written as fractions. When a decimal or fractional approximation for an irrational number is used to compute (as in finding the area of a circle), the answer is always approximate and should clearly indicate this.

Step-by-step explanation:

hope i helped

8 0
3 years ago
Help me answer this but hurry please!
Andrew [12]

Answer:

165°

Step-by-step explanation:

4 0
3 years ago
The composite figure is made up of a triangular prism and a pyramid. The two solids have congruent bases. A triangular pyramid i
Darina [25.2K]

Answer:

the answer is 3465

Step-by-step explanation:

got it right on ed

4 0
3 years ago
Read 2 more answers
What is the simplest multicellular organism?
grigory [225]
The simplest multicecullar organism is alga
7 0
3 years ago
What is the area of the shaded region in the figure below ? Leave answer in terms of pi and in simplest radical form
ser-zykov [4K]

Answer:

Step-by-step explanation:

That shaded area is called a segment. To find the area of a segment within a circle, you first have to find the area of the pizza-shaped portion (called the sector), then subtract from it the area of the triangle (the sector without the shaded area forms a triangle as you can see). This difference will be the area of the segment.

The formula for the area of a sector of a circle is:

A_s=\frac{\theta}{360}*\pi r^2 where our theta is the central angle of the circle (60 degrees) and r is the radius (the square root of 3).

Filling in:

A_s=\frac{60}{360}*\pi (\sqrt{3})^2 which simplifies a bit to

A_s=\frac{1}{6}*\pi(3) which simplifies a bit further to

A_s=\frac{1}{2}\pi which of course is the same as

A_s=\frac{\pi}{2}

Now for tricky part...the area of the triangle.

We see that the central angle is 60 degrees. We also know, by the definition of a radius of a circle, that 2 of the sides of the triangle (formed by 2 radii of the circle) measure √3. If we pull that triangle out and set it to the side to work on it with the central angle at the top, we have an equilateral triangle. This is because of the Isosceles Triangle Theorem that says that if 2 sides of a triangle are congruent then the angles opposite those sides are also congruent. If the vertex angle (the angle at the top) is 60, then by the Triangle Angle-Sum theorem,

180 - 60 = 120, AND since the 2 other angles in the triangle are congruent by the Isosceles Triangle Theorem, they have to split that 120 evenly in order to be congruent. 120 / 2 = 60. This is a 60-60-60 triangle.

If we take that extracted equilateral triangle and split it straight down the middle from the vertex angle, we get a right triangle with the vertex angle half of what it was. It was 60, now it's 30. The base angles are now 90 and 60. The hypotenuse of this right triangle is the same as the radius of the circle, and the base of this right triangle is \frac{\sqrt{3} }{2}. Remember that when we split that 60-60-60 triangle down the center we split the vertex angle in half but we also split the base in half.

Using Pythagorean's Theorem we can find the height of the triangle to fill in the area formula for a triangle which is

A=\frac{1}{2}bh. There are other triangle area formulas but this is the only one that gives us the correct notation of the area so it matches one of your choices.

Finding the height value using Pythagorean's Theorem:

(\sqrt{3})^2=h^2+(\frac{\sqrt{3} }{2})^2 which simplifies to

3=h^2+\frac{3}{4} and

3-\frac{3}{4}=h^2 and

\frac{12}{4} -\frac{3}{4} =h^2 and

\frac{9}{4} =h^2

Taking the square root of both the 9 and the 4 (which are both perfect squares, thankfully!), we get that the height is 3/2. Now we can finally fill in the area formula for the triangle!

A=\frac{1}{2}(\sqrt{3})(\frac{3}{2}) which simplifies to

A=\frac{3\sqrt{3} }{4}

Therefore, the area in terms of pi for that little segment is

A_{seg}=\frac{\pi}{2}-\frac{3\sqrt{3} }{4}, choice A.

8 0
3 years ago
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