Question

What is the equilibrium constant expression for the given reaction?

Answer 1

K = [CO₂]
.................
:)

Answer 2

Answer: Option (c) is the correct answer.

Explanation:

At equilibrium the relationship expressed between the amounts of concentration of products and reactants in a reversible chemical reaction is known as equilibrium constant.

The concentration of solids and liquids is considered equal to 1 in equilibrium constant.

For example, in the given reaction $CaCO_{3}(s) \rightleftharpoons CaO(s) + CO_{2}(g)$

Therefore, its equilibrium constant will be as follows.

          $K_{eq} = \frac{[CO_{2}][CaO]}{CaCO_{3}}$

Here concentration of $CaCO_{3}$ and CaO is 1 as these are solids.

Thus, equilibrium constant expression will be as follows.

           $K_{eq} = [CO_{2}]$