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faust18 [17]
3 years ago
7

The dimensions of Rectangle A are 6 times the dimensions of Rectangle B. How do the areas of the Rectangles compare

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
3 0
The area of Rectangle A will always be 36 times the area of Rectangle B.

For example:
If Rectangle B has length 1 and width 2, Rectangle A will have length 6 and width 12. By multiplying, Rectangle A will have an area of 72 and B 2. Divide the two numbers and you will have 36. 

Feel free to try with other numbers if you want to test it out.
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X^2+y^2-4y-15=6
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If the length of a cuboid is 60cm and width 40cm and its surface area is 14800cm² find its height
kherson [118]
Formula of surface area of cuboid = 2(lb+bh+lh) . Surface area of cuboid is 14800cm^2 (Given) then 14800 = 2(60*40+40*Height+Height*60) 14800= 2(2400+40*H+H*60) 14800= 4800+80*2H+2H*60 14800= 4880*4H*60 14800/4880*60= 4H
14800/292800=4H
7400/146400=4H
3700/73200=4H
1850/36600=4H
925/18300=4H
185/3660=4H
37/732=4H
37/732*4=H
37/2928=H
H= 79.1351351
3 0
2 years ago
Read 2 more answers
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