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AVprozaik [17]
3 years ago
14

The length of the segment is centimeters. The scale is cm : m.

Mathematics
1 answer:
Art [367]3 years ago
3 0
Where is the scale :’v
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Solve the inequality 7(x + 4) > 0.
matrenka [14]

Answer:

x > - 4

Step-by-step explanation:

Given

7(x + 4) > 0 ← distribute left side

7x + 28 > 0 ( subtract 28 from both sides )

7x > - 28 ( divide both sides by 7 )

x > - 4

3 0
3 years ago
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How is mathematics done?​
Ad libitum [116K]

Answer:

Mathematics can be completed through the use of logical thinking and the use of equations to figure out various problems.

8 0
3 years ago
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WILL GIVE BRAINLIEST !!!
wel

Answer:

72-12k plz mark brainlest

Step-by-step explanation:

7 0
3 years ago
A. 115<br> B. 167<br> C. 126<br> D. 96
geniusboy [140]

Answer:

126

Step-by-step explanation:

Let x be the missing length

The triangles are similar:

● UE/140 = 45/x

From the graph we deduce that:

● UE = 140 - 90 = 50

Replace UE by its value

● 50/ 140 = 45/x

Switch x and 50

● x / 140 = 45/50

45/50 is 9/10 wich is 0.9

● x/140 = 0.9

Multiply 0.9 by 140

● x = 140 × 0.9

● x = 126

5 0
3 years ago
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I need to use the Pythagorean Theorem to find X. I don’t know how to do that!!
frutty [35]

Answer:

17) x=8

18) x=\sqrt{189} or x= 3\sqrt{21}

Step-by-step explanation:

So the rule is a^{2} +b^{2} =c^{2}, "c" being the hypothenuse, or the long line that is opposite to the right angle.

17) We know that both values of x are equal to each other, which makes everything 10x easier!

                                               x^{2} +x^{2} =(8\sqrt{2})  ^{2}

(by the way we know the x values are our a and b values because they are legs! the way I like to remember the legs is that they are connected to the right angle box, and therefore support the hypothenuse)

<em>simplify</em> (╥︣﹏╥)    

                                                2x^2=8^2(\sqrt{2} )^{2}  

                                                  2x^2=64(2)

                                                   2x^2=128    

                                                  x^{2}= 128/2  

                                                     x^{2} =64

                                                        x=8      

18) Just pretend that the flipped triangle doesn't exist. It's parallel to the other triangle with values on it, and basically servers no purpose other than being parallel to the sister triangle :)

Anyways, since we know the hypothenuse (15) but we don't know one of our leg values (x), we're going to change our equation a bit!

                                                    c^{2} - b^{2} = a^{2}

It doesn't matter if you put the one leg value in a or b, just as long as you stick to that same equation you started with the entire time!

                                                   15^{2} -6^{2} =x^{2}

                                                   225-36=x^{2}  

                                                     x^{2} =189

                                               x=\sqrt{189}=3\sqrt{21}

        The more you do these, the easier they'll get, so don't worry!

                           

4 0
3 years ago
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