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Sindrei [870]
3 years ago
14

Can someone help with 18

Mathematics
1 answer:
Neporo4naja [7]3 years ago
5 0
= 8xy - x -2xy + 3x
= 6xy + 2x ..............combine like terms

answer
3.    6xy + 2x 
You might be interested in
The sum of the first 130 positive even integers
Triss [41]

Answer:

Step-by-step explanation:

Positive integers are of the form 2n

The first term is 2 and the 130th term is 2(130)=260

The sum of this arithmetic sequence is the average of first and last terms times the number of terms

(2+260)(130/2)

17030

7 0
3 years ago
The fraction 3/10 is the difference of 8/10 and which fraction
Mars2501 [29]

Answer:

½ or 11/10

Step-by-step explanation:

3/10 = 8/10 - X

X = 8/10 - 3/10 = 5/10 = 1/2

Or,

X - 8/10 = 3/10

X = 11/10

5 0
3 years ago
Read 2 more answers
I need help solving this equation
jok3333 [9.3K]

-5y+1y=-1+9

-4y=8

y=2

I think thats the answer

5 0
3 years ago
Read 2 more answers
What will be the answer?
Crazy boy [7]

Answer:

270

Step-by-step explanation:


5 0
3 years ago
Help please!!! Ty to anyone who answeres
Alja [10]

Answer:

<em>Scale factor=2</em>

<em>The perimeter of the enlarged figure is 19</em>

<em>The area of the enlarged figure is 4 times the area of the original figure</em>

Step-by-step explanation:

<u>Scaling</u>

There are two figures, the red rectangle (original) and the blue rectangle (enlarged).

To find the scale factor we directly compare the height of both rectangles and note:

height of original rectangle=1.5

height of enlarged rectangle=3

Thus, the scale factor is 3/1.5 = 2

Scale factor=2

The original perimeter is calculated as:

P1=2*1.5+2*3.25=3+6.5=9.5

The perimeter of the enlarged figure is 2 times the original perimeter

P2=2*9.5=19

The perimeter of the enlarged figure is 19

To calculate the area of the enlarged figure, we use

A2=H2*W2

Where H2 and W2 are the height and width of the enlarged figure.

Since

H2=2*H1

W2=2*W1

A2=4*A1

The area of the enlarged figure is 4 times the area of the original figure

6 0
3 years ago
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