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Gala2k [10]
3 years ago
11

Find the measure of angle y. Round your answer to the nearest hundredth. (please type the numerical answer only)

Mathematics
1 answer:
Mars2501 [29]3 years ago
6 0
50 degrees because you didnt tell us anything how can we answer this.
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Two customers went to the post office to buy postcards and large envelopes. Each postcard costs the same amount and each large e
anygoal [31]

Answer:

The first one $1.42

Step-by-step explanation:

1.42x5=7.1 (cost of all envelopes)

12-7.1=4.9

4.9/14=0.35 (one postcard)

10 postcards= 3.5

1.42x15=21.3 (cost of all envelopes)

3.5+21.3=$24.80

7 0
2 years ago
Jinny is selling bracelets for $4.00. So far, she has earned $296.00. She needs to earn more than $472.00 in order to meet her g
Darya [45]
She needs more then 472 and has 296 so she still needs 176 because 472-296=176
Each bracelets is 4 so then 176/4 is 44
1. She needs to sell 44 more bracelets,45 if she needs more than 472
2 the inequality would be x>=44 bracelets
7 0
3 years ago
If I have a mass of 40g and a volume of 20ml, then what is the density?
nydimaria [60]

Answer:

2g/mL^3

Step-by-step explanation:

To find density, we use mass/volume. 40g is the mass and 20mL is the volume. 40/20 is 2, therefore, 2g/mL^3

6 0
3 years ago
Read 2 more answers
If a car is moving at the speed of 60 miles per hour how many miles would a car travel i 120 minutes
sertanlavr [38]

Answer:

120 miles

Step-by-step explanation:

120minutes= 2hour

2×60÷1=120 (miles)

8 0
3 years ago
In a study of government financial aid for college​ students, it becomes necessary to estimate the percentage of​ full-time coll
ICE Princess25 [194]

Answer:

a) n = 1037.

b) n = 1026.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

​(a) Assume that nothing is known about the percentage to be estimated.

We need to find n when M = 0.04.

We dont know the percentage to be estimated, so we use \pi = 0.5, which is when we are going to need the largest sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 2.575\sqrt{\frac{0.5*0.5}{n}}

0.04\sqrt{n} = 2.575*0.5

(\sqrt{n}) = \frac{2.575*0.5}{0.04}

(\sqrt{n})^{2} = (\frac{2.575*0.5}{0.04})^{2}

n = 1036.03

Rounding up

n = 1037.

(b) Assume prior studies have shown that about 55​% of​ full-time students earn​ bachelor's degrees in four years or less.

\pi = 0.55

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 2.575\sqrt{\frac{0.55*0.45}{n}}

0.04\sqrt{n} = 2.575*\sqrt{0.55*0.45}

(\sqrt{n}) = \frac{2.575*\sqrt{0.55*0.45}}{0.04}

(\sqrt{n})^{2} = (\frac{2.575*\sqrt{0.55*0.45}}{0.04})^{2}

n = 1025.7

Rounding up

n = 1026.

6 0
3 years ago
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