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drek231 [11]
3 years ago
5

Jake has a bag of 50 beads, some of which are blue and the remaining are green. Jake randomly pulls out a bead from the bag, rec

ords the color, and replaces it in the bag. Jake has already recorded 14 blue and 6 green beads. Based on these results, what is most likely the number of blue beads in the bag?
{A} 15
{B} 20
{C} 30
{D} 35
Mathematics
2 answers:
miv72 [106K]3 years ago
5 0

Answer:

15

Step-by-step explanation:

14 and 6 added together are 20, there are two sets of 20 and one 10 left over.  that means 6 + 6 + 3 = 15

Your answer is A, 15

lana [24]3 years ago
3 0
It should be D: 35. 14 + 6 = 20. I just multiplied that by two, which equals 40. That means there are 2 sets of 14 and 2 sets of 6. Since there is 10 leftover, I divided both by 2. 7 + 3 = 10. 14 x 2 = 28 + 7 = 35
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How to determine relationship between two variables with standard deviation?
luda_lava [24]
Standard deviation is the average distance between two points on the graph. If the standard deviation (sd) is high, then the variables relationship is more spread out and unlike one another. The smaller the sd, the closer and less varied the variables are.
6 0
3 years ago
Which expression would represent the cost of one CD, if the total cost for three of them is $362
Fiesta28 [93]

Answer:

One CD would've been 120.67

Someone correct me if I'm wring please

8 0
3 years ago
Six​ stand-up comics,​ A, B,​ C, D,​ E, and​ F, are to perform on a single evening at a comedy club. The order of performance is
kiruha [24]

Answer:

a) 1/6

b) 1/36

c) 1/720

d) 1/3

Step-by-step explanation:

a) Any of the six comics can perform in the fourth place, so there is one chance in six that Comic F is the one that performs fourth.

P(F=4th)=1/6

b) In this case, we have two conditions. Both are independent of each other, so the probability of both happening is the product of the probabilities of each happening individually:

P(D=4th \&B=2nd)=P(D=4th)\cdot P(B=2nd)=(1/6)\cdot(1/6)=1/36

c) This combination is one in all possible orders of perform. The amount of combinations of orders is n!=6!=720 possible combinations. So the probability of this specific order is:

P(F, D, B, A, C, E)=1/720

d) In this case, of the six possible comics performing in the last place, we calculate the probability of 2 of them being in that place. So the probability is:

P(C=6th\,or\, E=6th)=2/6=1/3

8 0
3 years ago
How do you solve the equation 3x = 9 by multiplying 3 to both sides
notka56 [123]
Whenever you see <em>x </em> next to a 3, and it says that it equals 9, you know that 3•3=9.
5 0
3 years ago
Read 2 more answers
Need help fast due today thanks
cricket20 [7]

1

Move everything to the left by subtracting 25 from both sides:

81x^2-25=0

Both terms are squares: 81x^2 is the square of 9x, while 25 is the square of 5. So, we can apply the factoring

a^2-b^2=(a+b)(a-b)

To factor the expression as

(9x+5)(9x-5)=0

A multiplication is zero if and only if one of the factors is zero, so we have

(9x+5)(9x-5)=0 \iff 9x+5=0 \lor 9x-5=0 \iff x=-\dfrac{5}{9} \lor x=\dfrac{5}{9}

2

The discriminant of the quadratic expression ax^2+bx+c is defined as

\Delta = b^2-4ac

So, you have

\Delta = 0^2-4\cdot(-1)\cdot(-25) = -100

3

Similarly, we have

\Delta = 7^2-4\cdot(-3)\cdot 6 = 49+72=121

8 0
3 years ago
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