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skelet666 [1.2K]

3 years ago

7

One baseball team played 36 games throughout their entire season. If this baseball team won 18 of those games, then what percent

age of their games did they win?

1 answer:

gizmo_the_mogwai [7]3 years ago

7 0

They have won 50% of their games.

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18 24 11 What is the area of the triangle shown? A.99 square units

vodomira [7]

Answer: I think B

Step-by-step explanation:

8 0

3 years ago

grin007 [14]

-3+7=4

-8+4=-4

-16+4=-12

24-16=8

-14+6=-8

3+(-8)=-5

-31+(-45)=-76

-42-25=-67

-30+1=-29

-3-29=-32

72-50=22

15-2=13

-23-15=-38

2-1=1

-5-4=-9

6 0

3 years ago

hector and alex traded video games. alex gave hector one fourth of his video games in exchange for 6 video games. then he sold 3

oksian1 [2.3K]

Answer:

20 games

Step-by-step explanation:

Lets work backwards; *Adding what he gave away or lost*

-Alex started with 16 video games

-Add the games gave to his brother (+2)

-Add the games he sold (+3)

-The number is 3/4 of his games

-Subtract the games he traded with hector (-1/4)

Equation: 16+2+3-6= 3/4 X (variable) *You can choose other than X*

21-6 = 15

15 = 3/4

Take the reciprical of 3/4 which is 4/3 and multiply it by both sides

4/3 x 15 = 3/4 x 4/3

4/3 X 15 = 20!

ALEX STARTED WITH <em>20 GAMES!</em>

<em></em>

3 0

3 years ago

Darren invests $4,500 into an account that earns 5% annual interests. How much will be in the account after 10 years if the inte

Tom [10]

We have been given that Darren invests $4,500 into an account that earns 5% annual interests. We are asked to find the amount in his account after 10 years, if the interest rate is compounded annually, quarterly, monthly, or daily.

We will use compound interest formula to solve our given problem.

$A=P(1+\frac{r}{n})^{nt}$ , where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

$5\%=\frac{5}{100}=0.05$

When compounded annually, $n=1$ :

$A=4500(1+\frac{0.05}{1})^{1\cdot 10}$

$A=4500(1.05)^{10}$

$A=4500(1.6288946267774414)$

$A=7330.025820498\approx 7330.03$

When compounded quarterly, $n=4$ :

$A=4500(1+\frac{0.05}{4})^{4\cdot 10}$

$A=4500(1.0125)^{40}$

$A=4500(1.6436194634870132)$

$A=7396.28758569\approx 7396.29$

When compounded monthly, $n=12$ :

$A=4500(1+\frac{0.05}{12})^{12\cdot 10}$

$A=4500(1.00416666)^{120}$

$A=4500(1.64700949769)$

$A=7411.542739605\approx 7411.54$

When compounded daily, $n=365$ :

$A=4500(1+\frac{0.05}{365})^{365\cdot 10}$

$A=4500(1.0001369863013699)^{3650}$

$A=4500(1.6486648137656943695)$

$A=7418.9916619456\approx 7419.00$

Since amount earned will be maximum, when interest is compounded daily, therefore, Darren should use compounded daily interest rate.

3 0

3 years ago

31=4-9y I need help sorry

Drupady [299]

Answer:

y=-3

Step-by-step explanation:

31=4-9y

9y=4-31

9y=-27

y=-27/9

y=-3

8 0

3 years ago