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3 years ago

Reduce the following fraction to lowest terms 49/105

Mathematics

2 answers:

iren [92.7K]3 years ago

8 0

These 2 numbers are both divisible by 7

(49 / 7) / (105 / 7) = 7 / 15 <== lowest terms

Alchen [17]3 years ago

5 0

Reduce by dividing top and bottom by 7, =7/15

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tamaranim1 [39]

9514 1404 393

Answer:

a ≈ 4.68

Step-by-step explanation:

The law of cosines tells you ...

a² = b² +c² -2bc·cos(A)

a = √(b² +c² -2bc·cos(A))

a = √(5² +8² -2·5·8·cos(33°)) = √(25 +64 -80·0.83867) ≈ √21.906

a ≈ 4.68

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What is 238 rouned to the nearst houndred

Alexeev081 [22]

200 because:
250 or higher is 300
249 or lower is 200

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2 years ago

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Iodine-125 has a half-life of about 60 days. How many milligrams of a 1000 mg sample will remain after 240 days?

Tomtit [17]

240 days is 4 times the half-life, which means that a sample of 1000 mg will decay to

$\dfrac{1000}{2^4}=\dfrac{125}2=62.5\,\mathrm{mg}$

after 240 days.

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3 years ago

1. Which point on the axis satisfies the inequality y

grigory [225]

Answer:

1) Point $(1,0)$ -----> see the attached figure N $1$

2) The value of x is $4$

3) I quadrant

4) $(1,1)$

5) $y>-5x+3$

Step-by-step explanation:

Part 1)

we know that

If the point satisfy the inequality

then

the point must be included in the shaded area

The point $(1,0)$ is included in the shaded area

Part 2)

we have

$x-2y\geq 4$

see the attached figure N $2$

we know that

The value for x on the boundary line and the x axis is equal to the x-intercept of the line $x-2y= 4$

For $y=0$

Find the value of x

$x-2(0)= 4$

$x=4$

The solution is $x=4$

Part 3)

we have

$x\geq 0$ -----> inequality A

The solution of the inequality A is in the first and fourth quadrant

$y\geq 0$ -----> inequality B

The solution of the inequality B is in the first and second quadrant

the solution of the inequality A and the inequality B is the first quadrant

Part 4) Which ordered pair is a solution of the inequality?

we have

$y\geq 4x-5$

we know that

If a ordered pair is a solution of the inequality

then

the ordered pair must be satisfy the inequality

we're going to verify all the cases

case A) point $(3,4)$

Substitute the value of x and y in the inequality

$x=3,y=4$

$4\geq 4(3)-5$

$4\geq 7$ ------> is not true

therefore

the point $(3,4)$ is not a solution of the inequality

case B) point $(2,1)$

Substitute the value of x and y in the inequality

$x=2,y=1$

$1\geq 4(2)-5$

$1\geq 3$ ------> is not true

therefore

the point $(2,1)$ is not a solution of the inequality

case C) point $(3,0)$

Substitute the value of x and y in the inequality

$x=3,y=0$

$0\geq 4(3)-5$

$0\geq 7$ ------> is not true

therefore

the point $(3,0)$ is not a solution of the inequality

case D) point $(1,1)$

Substitute the value of x and y in the inequality

$x=1,y=1$

$1\geq 4(1)-5$

$1\geq -1$ ------> is true

therefore

the point $(1,1)$ is a solution of the inequality

Part 5) Write an inequality to match the graph

we know that

The equation of the line has a negative slope

The y-intercept is the point $(3,0)$

The x-intercept is a positive number

The solution is the shaded area above the dashed line

the equation of the line is $y=-5x+3$

The inequality is $y>-5x+3$

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Masja [62]

Answer:

The radius is always half of the diameter.

Step-by-step explanation:

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