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ArbitrLikvidat [17]
3 years ago
15

An 80-ounce bottle of apple juice contains 32 ounces of water. A 64-ounce bottle of orange juice has 48 ounces of water. Which j

uice has a greater percent of water?
Mathematics
1 answer:
Sliva [168]3 years ago
7 0

Answer:

<u>Orange juice</u> has a greater percent of water.

Step-by-step explanation:

Given:

An 80-ounce bottle of apple juice contains 32 ounces of water. A 64-ounce bottle of orange juice has 48 ounces of water.

Now, to find in which juice greater percent of water is there.

An 80-ounce bottle of apple juice contains 32 ounces of water.

Total ounces of juice = 80.

Total ounces of water = 32.

So, to get the percent of water:

\frac{32}{80}\times 100

=0.4\times 100

=40\%.

Now,

A 64-ounce bottle of orange juice has 48 ounces of water.

Total ounces of juice = 64.

Total ounces of water = 48.

So, to get the percent of water in bottle of orange juice:

\frac{48}{64} \times 100

=0.75\times 100

=75\%.

<u><em>Thus, in bottle of orange juice contains 75% of water and in bottle of apple juice contains 40% of water.</em></u>

Therefore, orange juice has a greater percent of water.

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∠ 2 = 45°

Step-by-step explanation:

∠ 1 and ∠ 2 are same- side interior angles and are supplementary, thus

∠ 2 = 180° - ∠ 1 = 180° - 135° = 45°

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Jason puts $30 worth of gas in his truck. The price per gallon was $2.50. Which equation can be solved to find the number of gal
tankabanditka [31]

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Consider the polynomial p(x) = x^3 + 4x^2 + 6x − 36.
Nady [450]

Answer:

a. attached graph; zero real: 2

b. p(x) = (x - 2)(x + 3 + 3i)(x + 3 - 3i)

c. the solutions are 2, -3-3i and -3+3i

Step-by-step explanation:

p(x) = x³ + 4x² + 6x - 36

a. Through the graph, we can see that 2 is a real zero of the polynomial p. We can also use the Rational Roots Test.

p(2) = 2³ + 4.2² + 6.2 - 36 = 8 + 16 + 12 - 36 = 0

b. Now, we can use Briott-Ruffini to find the other roots and write p as a product of linear factors.

2 |  1     4     6    -36

     1      6    18     0

x² + 6x + 18 = 0

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√Δ = 6i

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x' = -3-3i

x" = -3+3i

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