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mihalych1998 [28]
3 years ago
5

Jezebel took a train to visit her uncle. The train traveled at a constant speed of 40 miles per hour. Complete the table.​ Then,

write an equation to find the total distance d traveled after t hours.

Mathematics
2 answers:
PtichkaEL [24]3 years ago
5 0
Multiply 40 by that number so basically y=Mx+b
sergiy2304 [10]3 years ago
4 0

Answer:

[see below]

Step-by-step explanation:

We can tell that for every hour passed the distance traveled by the train would increase by 40 miles.

We can use the equation d = 40t to determine the values of the table. The 'd' is total distance and 't' is the number of given hours.

Two hours:

d = 40(2)

d = 80

Three Hours:

d = 40(3)

d = 120

Four Hours:

d = 40(4)

d = 160

Hope this helps.

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N × $3.05 = $305.00=
sdas [7]

Answer:

n = 100

Step-by-step explanation:

Step 1:

n × $3.05 = $305            Equation

Step 2:

n = $305 ÷ $3.05          Divide

Answer:

n = 100

Hope This Helps :)

4 0
3 years ago
A light bulb consumes 3120 watt-hours in 3 days and 6 hours. How many watt-hours does it consume per day?
matrenka [14]

2850*24/(4*24+18)

The light bulb consumes 600 watt-hours per day.

6 0
3 years ago
Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2
Vsevolod [243]

Answer:

Given that:

a = (\frac{x+ip}{2})^{\frac{1}{2}} and a+= (\frac{x-ip}{2})^{\frac{1}{2}}

if a , a+ commutator, it obeys aa^+ = a^+a

First find:

aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}

                = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

Now;

a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}

              =(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

therefore, aa^+ = a^+a which implies the operators a and a+ are commutators.    


7 0
3 years ago
Use integer values of x from -3 to 3 to graph the equation <br><br> y = 1/3 [x] - 2
jekas [21]
Y=1/3[-3]-2 I think is the answer
4 0
3 years ago
A gambling casino is designed in the shape of a square pyramid with a side length of 75 ft. The height of the building is 28 ft.
irakobra [83]

Answer:

Step-by-step explanation:

Given the dimension of a square pyramid

Length of pyramid

L = 75 ft

Height of pyramid

H = 28ft

The pyramid is a square base

Then,

Volume of a pyramid is calculated using

Volume = base area × height

Since base is a square, then the area of a square is

Area = L² = 75² = 5625 ft²

Then,

Volume = base Area × height

Volume = 5625 × 28

Volume = 157,500 ft³

Then, given the rate of volume to be

dV / dt = 26,250 ft³ / hr

So, we want to find the time the system will filled the air

dV / dt = 26,250

dV = 26,250 dt

Integrate both sides

∫ dV = ∫ 26,250 dt

V = 26,250t + C

When t = 0, V = 0, initially, there is not volume of system air.

Therefore C = 0

V = 26,250t

When V = 157,500 ft³

Then,

t = V / 26,250

t = 157,500 / 26,250

t = 6 hours

So, it will take 6 hours for the system to circulate the room

5 0
3 years ago
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