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Katarina [22]
3 years ago
10

Can someone please help me on this question

Mathematics
1 answer:
Anastasy [175]3 years ago
3 0
(7,-3)
..................
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A coin is flipped 50 times. In those 50 trials, 29 of the flips resulted in heads. What is the experimental probability of a coi
Oksana_A [137]
Close to 25% I'm guessing. Maybe 30
8 0
3 years ago
Read 2 more answers
Tina, Sijil, Kia, vinayash Alisha and shifa are playing game by forming two teams. Three players in each team how many different
IgorC [24]

Answer:

20

Step-by-step explanation:

GIVEN: Tina, Sijil, Kia, vinayash Alisha and shifa are playing game by forming two teams Three players in each team.

TO FIND: how many different ways can they be put into two teams of three players.

SOLUTION:

Total number of players =6

total teams to be formed =2

total players in one team =3

we have to number of ways of selecting 3 players for one team, rest 3 will go in other team.

Total number of ways of selecting 3 players =^6C_3

                                                                      =\frac{6!}{3!3!}

                                                                     =20

Hence total number of different ways in which they can be put into two different teams is 6

5 0
3 years ago
3.) (4 x 9 - 21) \ 3+6^2
nignag [31]

Answer:

41

Step-by-step explanation:

Given Expression:

(4 x 9 - 21) \ 3+6^2

Multiply 4 and 9 to get 36.

36 - 21 / 3 + 6^2

Subtract 21 from 36 to get 15.

15/3 + 6^2

Divide 15 by 3 to get 5.

5+6^2

Calculate 6 to the power of 2 and get 36.

5+36

Add 5 and 36 to get 41.

41

3 0
3 years ago
Cards with the numbers 1 through 40 are placed in a box and thoroughly shuffled.
MrRa [10]

9/40 + 2/40 = 11/40

hope this helps

7 0
3 years ago
Let f(x)= -5x+10 then f(-2)=<br><br> Simple functions
valentina_108 [34]
F(x) = -5 x + 10
Then
f(-2) = -5(-2) + 10
= 10 + 10
= 20
8 0
3 years ago
Read 2 more answers
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