Answer: 82°
Step-by-step explanation:
<CDE = far arc - near arc / 2
i.e
<CDE = arcCBE - arcCE / 2
arcCE = 98°
arcCBE = 360° - 98° = 262°
<CDE = 262° - 98° / 2
<CDE = 164 / 2
<CDE = 82°
Therefore the measure of < CDE is 82°
The perimeter is 1/2 the perimeter of ABCD because the scale factor is 1/2. It would be 10 units.
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