Answer:
Amelia rented a DVD and it was due to be returned on 26 November. She actually returned it to the shop on 12 December. The rental shop applies a fine of 9p for every day the DVD is overdue.
Work out the total fine paid by Amelia. Give your answer in £
5 miles high is one of the sides of a triangle depending on accuracy level
h^2=x^2+y^2
we don't have 2 distances
Tan A=O/a
O=a tan A
We solve for O because the angle is at the top of the line going up and we want the opposite angle that is along the ground
O=5×tan(173.7/2)=90.854033512
The distance he can see is:
90.85*2~181.7 miles
Now we need to find the distance between lines:
The north south distance between each line is 69 miles
thus the number of degrees he will see will be:
181.7/69
=2 19/30
Answer:
an = 63(-1/3)^(n-1)
Step-by-step explanation:
This is a geometric sequence with first term 63 and common ratio -1/3.
The equation for the nth term is
an = 63(-1/3)^(n-1).
So in matt's equation, he made a mistake in the a transision from line 2 to line 3
in line 2: -4(-2)2
in line 3: -4(4)
the mistake is that -2 times 2 is not equal +4 it is equal to -4
also from lines 5 to 6 he made a mistake in order of opperations (mulit division then addition and subtract)
line 5: -10+30/5
line 6: 20/5
so he first subtracted 10 then divided, he should have divided then subtracted
so the equation should have equaled
Karen used the correct (-) times (+) property and the order of operations
so Karen is correct and Matt is wrong.
Answer:
![107^\circ, 133^\circ, 20^\circ, \text{and}, 23^\circ](https://tex.z-dn.net/?f=107%5E%5Ccirc%2C%20133%5E%5Ccirc%2C%2020%5E%5Ccirc%2C%20%5Ctext%7Band%7D%2C%2023%5E%5Ccirc)
Step-by-step explanation:
9. For the lines 'm' and 'n' to be parallel the sum of interior angles should be 180 degrees that is:
![x+73^\circ=180^\circ](https://tex.z-dn.net/?f=x%2B73%5E%5Ccirc%3D180%5E%5Ccirc)
![x=107^\circ](https://tex.z-dn.net/?f=x%3D107%5E%5Ccirc)
10. For the lines 'm' and 'n' to be parallel the alternate exterior angles should be equal that is:
![147^\circ=x+14^\circ](https://tex.z-dn.net/?f=147%5E%5Ccirc%3Dx%2B14%5E%5Ccirc)
![x=147^\circ-14^\circ](https://tex.z-dn.net/?f=x%3D147%5E%5Ccirc-14%5E%5Ccirc)
![x=133^\circ](https://tex.z-dn.net/?f=x%3D133%5E%5Ccirc)
11. For the lines 'm' and 'n' to be parallel alternate angles should be equal that is:
![180^\circ-3x=2x+20^\circ](https://tex.z-dn.net/?f=180%5E%5Ccirc-3x%3D2x%2B20%5E%5Ccirc)
Solving for 'x' we get:
![180^\circ-20^\circ=3x+2x](https://tex.z-dn.net/?f=180%5E%5Ccirc-20%5E%5Ccirc%3D3x%2B2x)
![5x=160^\circ](https://tex.z-dn.net/?f=5x%3D160%5E%5Ccirc)
![x=32^\circ](https://tex.z-dn.net/?f=x%3D32%5E%5Ccirc)
12. For the lines 'm' and 'n' to be parallel corresponding angles should be equal that is:
![(7x-11)^\circ=(4x+58)^\circ](https://tex.z-dn.net/?f=%287x-11%29%5E%5Ccirc%3D%284x%2B58%29%5E%5Ccirc)
![7x-4x=58^\circ+11^\circ](https://tex.z-dn.net/?f=7x-4x%3D58%5E%5Ccirc%2B11%5E%5Ccirc)
![3x=69^\circ](https://tex.z-dn.net/?f=3x%3D69%5E%5Ccirc)
![x=\frac{69}{3}=23^\circ](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B69%7D%7B3%7D%3D23%5E%5Ccirc)