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sveticcg [70]
3 years ago
8

What is the ratio of the wavelengths of these two notes?

Mathematics
2 answers:
Vinil7 [7]3 years ago
7 0
The answer to this question is C . 4to 3
ryzh [129]3 years ago
5 0
Your best answer would be D but i aint smart so i dont know random guess
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Brad is having a party and buys a large cube of cheddar cheese at the market. The cube is 4 inches in height. When Brad gets hom
Naddika [18.5K]

Answer:

32 cubic inches

Step-by-step explanation:

4^3= 64

64/2= 32

3 0
2 years ago
19.87 but there’s a 20% discount what’s the answer now?
loris [4]
15.90 would be your new answer
4 0
2 years ago
Read 2 more answers
The length of a rectangle is 3131 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
Gala2k [10]

We have a rectangle with a diagonal included. That means we have to use Pythagorean's Theorem to find the missing dimensions. We start with the width as w. The length is 31 more than twice the width, so the length is 2w+31. The hypotenuse (diagonal) is 2 more than the length, so the diagonal measures 2w+33. In a right triangle, the hypotenuse is always the longest side, so we set up Pythagorean's Theorem using the bolded values as such: (2w+33)^2=w^2+(2w+31)^2. Distributing by multiplying we simplify to 4w^2+132w+1089=w^2+4w^2+124w+961. We need to solve for w. Once we do that we can use that value to find the length. What's nice is that the 4w^2 terms cancel each other out. So when we combine like terms and get them all on one side of the equals sign to factor we have w^2-8w-128=0. The 2 numbers that add up to -8 and multiply to -128 are 16 and -8. So the width is either 16 inches or the width is -8 inches. The 2 things in math that will never EVER be negative are time and distance/length. So -8 is out. The width is 16 inches. That means that the length is 2(16)+31, which is 63 inches. There you go!

8 0
3 years ago
Which algebraic expression can be used to find the nth term in the following sequence?
Agata [3.3K]

Answer:

n+4 is the final answer.

8 0
3 years ago
Can you help me with this problem please
Over [174]

Remark

I think you want us to do both 3 and 4


Three

QR is 4 points going left from the y axis + 2 points going right from the y axis.

QR = 6 units long.


RT is 4 units above the x axis and 3 units below the x axis

RT = 7 units long


TS = 3 units. For this one you just go from T to S. The graph really helps you. You just need to count.


Problem 4

You need to find the area of the combined figure. You could do it as a trapezoid, which might be the easiest way. I'll do that first.


Area = (b1 + b2)*h/2


Givens

B1 = QR = 6

B2 = UT + TS = 6 + 3 = 9

h = RT = 7


Area

Area = (6 + 9)*7/2

Area = 15 * 7 / 2

Area = 52.5


Comment

You could break this up into a rectangle + a triangle

Find the area of QRTU and add the Area of triangle RTS


<em>Area of the rectangle </em>= L * W

L = RT = 7

W = QR = 6

Area = 7 *6 = 42


<em>Area of the triangle</em> = 1/2 * B * H

B = TS = 3

H = RT =7

Area = 1/2 * 3 * 7

Area = 1/2 * 21

Area = 10.5


Total Area = 42 + 10.5 = 52.5 Both answers agree.

3 0
2 years ago
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