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Marysya12 [62]
3 years ago
7

When given an algebraic expression involving subtraction, why is it best to rewrite the expression using addition before identif

ying the terms?
Mathematics
1 answer:
kotykmax [81]3 years ago
7 0
<span>It is best to rewrite the expression using addition before identifying the terms because when you have subtraction figures, those would make a term negative. As a result, it would be easier to accidentally misinterpret a term that is negative as positive when evaluating an expression. Rewriting it using addition would put the negative terms in parenthesis and make it easier to transpose those terms and ensure correct identification and use.</span>
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Angle X is the larges angle in the triangle XYZ. Angle Y is the smallest angle. How does the sum of the measures of angles Y and
loris [4]
Dear Dollster444, the sum of angles Y and Z is bigger than Y.
3 0
3 years ago
A school debate team has 4 girls and 6 boys. A total of 3 of the team members will be chosen to participate in the district deba
mariarad [96]
There are 4+6=10 people in the team.
First calculate in how many ways you can choose 3 people from a group of 10 people, using combination:
(^{10} _3)=\frac{10!}{3!(10-3)!}=\frac{10!}{3! \times 7!}=\frac{7! \times 8 \times 9 \times 10}{6 \times 7!}=\frac{8 \times 9 \times 10}{6}=\frac{720}{6}=120
You can choose 3 people in 120 ways.

You can select 1 girl from a group of 4 girls in 4 ways.
Calculate in how many ways you can choose 2 boys from a group of 6 boys:
(^6 _2)=\frac{6!}{2! (6-2)!}=\frac{6!}{2! \times 4!}=\frac{4! \times 5 \times 6}{2 \times 4!}=\frac{5 \times 6}{2}=\frac{30}{2}=15
You can choose 2 boys in 15 ways.
Using the rule of product, you can calculate that you can choose 1 girl and 2 boys in 4×15=60 ways.

The probability of choosing 1 girl and 2 boys is the number of ways you can choose 1 girl and 2 boys divided by the number of ways you can choose 3 people from the group.
 P=\frac{60}{120}=\frac{1}{2}=50\%

The probability is 1/2, or 50%.
4 0
3 years ago
Two gamblers, call them Gambler A and Gambler B flip a coin repeatedly. The coin is unfair and comes up heads 2/3 of the time. G
Andru [333]

Answer:

≈ 0.52

Step-by-step explanation:

P( head ) = 2/3 , P( tail ) = 1/3

when a head is tossed ; Gambler A wins $1

when a tail is tossed : Gambler B wins $1

<u>Determine the P( Gambler A wins the game ) if he starts with I dollars</u>

Assuming I = $1

n = 5

p ( head ) = P( winning ) = 0.66

p( losing ) = 0.33

applying the conditional probability in Markov which is ;

Pₓ = pPₓ₊₁ + (1 - p) Pₓ₋₁

P( 1) = 0.66P₂ + 0.33P₀

resolving the above using with Markov probability

P( 1 ) = 0.51613

hence the probability of Gambler A winning the game if he starts with $1

≈ 0.52

6 0
3 years ago
Manuel and Sonja are shopping for school supplies. Manuel is buying 5 notebooks and 3 pens at a cost of $21. Sonja is buying 6 n
brilliants [131]

Answer: 6x+5y=28

Step-by-step explanation:

Looking at the first equation, we can tell that x stands for notebooks and y stand for pens. Since this talks about the total cost with the amount of products they bought, we can automatically eliminate the subtracting answer choices.

Now, we know that 6x+57=28 is the correct answer because Sonja bought 6 notebooks and 5 pens. This becomes 6x+5y.

3 0
3 years ago
Find the slope of the line through each pair of points
ddd [48]
The answer is 27/23. The way you listed the answers is confusing so I’m not giving a letter. Because [17+10]/[17+6]= 27/23
5 0
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