Dear Dollster444, the sum of angles Y and Z is bigger than Y.
There are 4+6=10 people in the team.
First calculate in how many ways you can choose 3 people from a group of 10 people, using combination:

You can choose 3 people in 120 ways.
You can select 1 girl from a group of 4 girls in 4 ways.
Calculate in how many ways you can choose 2 boys from a group of 6 boys:

You can choose 2 boys in 15 ways.
Using the rule of product, you can calculate that you can choose 1 girl and 2 boys in 4×15=60 ways.
The probability of choosing 1 girl and 2 boys is the number of ways you can choose 1 girl and 2 boys divided by the number of ways you can choose 3 people from the group.

The probability is 1/2, or 50%.
Answer:
≈ 0.52
Step-by-step explanation:
P( head ) = 2/3 , P( tail ) = 1/3
when a head is tossed ; Gambler A wins $1
when a tail is tossed : Gambler B wins $1
<u>Determine the P( Gambler A wins the game ) if he starts with I dollars</u>
Assuming I = $1
n = 5
p ( head ) = P( winning ) = 0.66
p( losing ) = 0.33
applying the conditional probability in Markov which is ;
Pₓ = pPₓ₊₁ + (1 - p) Pₓ₋₁
P( 1) = 0.66P₂ + 0.33P₀
resolving the above using with Markov probability
P( 1 ) = 0.51613
hence the probability of Gambler A winning the game if he starts with $1
≈ 0.52
Answer: 6x+5y=28
Step-by-step explanation:
Looking at the first equation, we can tell that x stands for notebooks and y stand for pens. Since this talks about the total cost with the amount of products they bought, we can automatically eliminate the subtracting answer choices.
Now, we know that 6x+57=28 is the correct answer because Sonja bought 6 notebooks and 5 pens. This becomes 6x+5y.
The answer is 27/23. The way you listed the answers is confusing so I’m not giving a letter. Because [17+10]/[17+6]= 27/23