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3 years ago

Determine if the equation defines y as a function of x: 2xy=1

1 answer:

3 0

Solve for y...

2xy=1

y=1/(2x)

So this is a function as each x value (with the exception of x=0) produces just one value for y. However, technically there is a vertical asymptote about the vertical line x=0. So there is a discontinuity as x=0.

I say this technically, because most would say that this function is true even with the discontinuity (as they do with say y=tana), but technically the discontinuity makes this not a function because another requirement of a function is for their to be an actual output value for each input value. In this case division by zero when x=0 is undefined and cannot be included as part of a function. So if you are picky about being absolute, 2xy=1 is really two functions. One with a domain of (-oo,0) and another with a domain of (0,+oo).

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Solve for x: 10 - 2x = -5x - 5<br> (1) X = -5<br> (3) X= 4<br> (2) x 15<br> (4)x= -15

Alekssandra [29.7K]

10 - 2x = -5x -5
+2x +2x
10 = -3x -5
+5 +5
15= -3x
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3 years ago

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What is the radius of the circle given by the equation below? x2 + 14x + y2 - 14y = -73

PolarNik [594]

Answer:

Step-by-step explanation: 5/13 8 48

graph the function, center the center of the circle find the difference between the center and the circle

center at (-7, 7)

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2 years ago

21 pointQuadrilateral QRST has diagonals that do NOT bisect each other, are congruent, and are not perpendicular. Which type of

Aleks [24]

Given:

Quadrilateral QRST has diagonals that do NOT bisect each other, are congruent and are not perpendicular.

By checking the options:

Rhombus, rectangle and the square each of them the diagonals bisect each other

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10 months ago

What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.

Paul [167]

Answer:

1.60 $ft^{2}$

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = $\pi$ $r^{2}$

So that,

for the inner part of the pipe,

r = $\frac{diameter}{2}$

= $\frac{5}{2}$

= 2.5 feet

Area of the inner part of the pipe = $\pi$ $r^{2}$

= 3.14 x $(2.5)^{2}$

= 19.625

Are of the inner part of the pipe is 19.63 $ft^{2}$ .

Total diameter of the pipe = 5 + 0.2

= 5.2 feet

r = $\frac{5.2}{2}$

= 2.6 feet

Area of the pipe = $\pi$ $r^{2}$

= 3.14 x $(2.6)^{2}$

= 21.2264

Area of the pipe is 21.23 $ft^{2}$ .

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

= 21.2264 - 19.625

= 1.6014

The cross sectional area of the cement pipe is 1.60 $ft^{2}$ .

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2 years ago

demarco wrote two correct variable expressions to represent the phrase “the product of a number and 7”. which variable expressio

Norma-Jean [14]

The question is asking to choose among the following choices that states the expressions that could be represented in the said phrase and in my further understanding, I would say that the answer would be n.7, I hope you are satisfied with my answer and feel free to ask for more

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2 years ago

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