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Leni [432]
3 years ago
5

Simplify this expression 3x+6x

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
5 0
9x would be the answer.
Ierofanga [76]3 years ago
4 0
Since both 3x and 6x have the variable x in it, we can just go ahead and add 3 and 6.

3x+6x=9x
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Firlakuza [10]

Answer:

(0,-3)

Step-by-step explanation:

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UNO [17]

9514 1404 393

Answer:

  A. 3×3

  B. [0, 1, 5]

  C. (rows, columns) = (# equations, # variables) for matrix A; vector x remains unchanged; vector b has a row for each equation.

Step-by-step explanation:

A. The matrix A has a row for each equation and a column for each variable. The entries in each column of a given row are the coefficients of the corresponding variable in the equation the row represents. If the variable is missing, its coefficient is zero.

This system of equations has 3 equations in 3 variables, so matrix A has dimensions ...

  A dimensions = (rows, columns) = (# equations, # variables) = (3, 3)

Matrix A is 3×3.

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B. The second row of A represents the second equation:

  0x_1+1x_2+5x_3=-1

The coefficients of the variables are 0, 1, 5. These are the entries in row 2 of matrix A.

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C. As stated in part A, the size of matrix A will match the number of equations and variables in the system. If the number of variables remains the same, the number of rows of A (and b) will reflect the number of equations. (The number of columns of A (and rows of x) will reflect the number of variables.)

6 0
3 years ago
Which statements are true about the median of a data set? Check all that apply. The median isn’t affected much by one outlier. T
sasho [114]
These are all the right answers:

The median isn’t affected much by one outlier.

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7 0
4 years ago
Read 2 more answers
If 28% of students in College are near-sighted, the probability that in a randomly chosen group of 20 College students, exactly
cluponka [151]

Answer: (D) 16%

Step-by-step explanation:

Binomial probability formula :-

P(x)=^nC_xp^x(1-p)^n-x, where n is the sample size , p is population proportion and P(x) is the probability of getting success in x trial.

Given : The proportion of students in College are near-sighted : p= 0.28

Sample size : n= 20

Then, the the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is given by :_

P(x=4)=^{20}C_4(0.28)^4(1-0.28)^{20-4}\\\\=\dfrac{20!}{4!16!}(0.28)^4(0.72)^{16}\\\\=0.155326604912\approx0.16\%

Hence, the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is closest to 16%.

7 0
3 years ago
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