I’m a little confused do you have a picture I could solve for cos then
Answer:
(0,-3)
Step-by-step explanation:
9514 1404 393
Answer:
A. 3×3
B. [0, 1, 5]
C. (rows, columns) = (# equations, # variables) for matrix A; vector x remains unchanged; vector b has a row for each equation.
Step-by-step explanation:
A. The matrix A has a row for each equation and a column for each variable. The entries in each column of a given row are the coefficients of the corresponding variable in the equation the row represents. If the variable is missing, its coefficient is zero.
This system of equations has 3 equations in 3 variables, so matrix A has dimensions ...
A dimensions = (rows, columns) = (# equations, # variables) = (3, 3)
Matrix A is 3×3.
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B. The second row of A represents the second equation:

The coefficients of the variables are 0, 1, 5. These are the entries in row 2 of matrix A.
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C. As stated in part A, the size of matrix A will match the number of equations and variables in the system. If the number of variables remains the same, the number of rows of A (and b) will reflect the number of equations. (The number of columns of A (and rows of x) will reflect the number of variables.)
These are all the right answers:
The median isn’t affected much by one outlier.
The median is the number in the middle of an ordered set of data.
To find the median of an even data set, find the average of the two middle numbers.
Hope this helped :)
Answer: (D) 16%
Step-by-step explanation:
Binomial probability formula :-
, where n is the sample size , p is population proportion and P(x) is the probability of getting success in x trial.
Given : The proportion of students in College are near-sighted : p= 0.28
Sample size : n= 20
Then, the the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is given by :_

Hence, the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is closest to 16%.