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3 years ago

Whoever get this right is brainest Evaluate 2/3-1/6

Mathematics

1 answer:

Mars2501 [29]3 years ago

6 0

Answer:

1/2 or 0.5

Step-by-step explanation:

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Lucy spends 4 hours a week babysitting. Her sister Lily spends seven eighths as much time babysitting. Does Lily babysit for mor

olganol [36]

Answer:

Lily babysit for less than 4 hours.

Step-by-step explanation:

Given:

Lucy spends in a week babysitting for 4 hours.

Lily spends seven-eighths of 4 hours.

Now, to find whether Lily babysit for more than 4 hours or less than that.

Number of hours Lucy babysit = 4 hours.

So, to get the hours Lily babysit:

$\frac{7}{8}\ of\ 4\ hours.$

$=\frac{7}{8}\times 4\\\\=\frac{28}{8} \\\\$

On simplifying we get:

$=\frac{7}{2} \\\\=3\frac{1}{2}\ hours.$

Thus, Lily spends $3\frac{1}{2}\ hours$ for babysitting which is less than 4 hours.

Therefore, Lily babysit for less than 4 hours.

4 0

3 years ago

Find the measure of the angle, round to the nearest tenth: Sin X = .7547

dimulka [17.4K]

SIN(x) = .7547
X = INVERSE-SIN(.7547)
X = 49.0 degrees

4 0

3 years ago

What is 5/16 divided by 2/3

gayaneshka [121]

You take 5/16 division you change it in matplication 3 goes up and 2 comes down so you numbers will be
5/16 times 3/2 you take 5 time3 is 15 and 16 times 2 is 32
So ur answer will be 15/32

8 0

3 years ago

An office is divided into 8 cubicles. How many of the cubicles are carpeted if only 1/4 of the cubicles are carpeted?

djyliett [7]

U have to do it like this 1/4 and 8/100

6 0

3 years ago

Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)

DENIUS [597]

Compute the necessary values/derivatives of $f(x)$ at $x=1$ :

$f(1)=3$

$f'(1)=2$

$f''(1)=-12$

$f'''(1)=-12$

$f^{(4)}(1)=48$

$f^{(5)}(1)=120$

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) $f(x)$ at $x=1$ by

$T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5$