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Ipatiy [6.2K]
3 years ago
7

Whoever get this right is brainest Evaluate 2/3-1/6​

Mathematics
1 answer:
Mars2501 [29]3 years ago
6 0

Answer:

1/2 or 0.5

Step-by-step explanation:

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Lucy spends 4 hours a week babysitting. Her sister Lily spends seven eighths as much time babysitting. Does Lily babysit for mor
olganol [36]

Answer:

Lily babysit for <u>less than 4 hours</u>.

Step-by-step explanation:

Given:

Lucy spends in a week babysitting for 4 hours.

Lily spends seven-eighths of 4 hours.

Now, to find whether Lily babysit for more than 4 hours or less than that.

Number of hours Lucy babysit = 4 hours.

So, to get the hours Lily babysit:

\frac{7}{8}\ of\ 4\ hours.

=\frac{7}{8}\times 4\\\\=\frac{28}{8} \\\\

<em>On simplifying we get:</em>

=\frac{7}{2} \\\\=3\frac{1}{2}\ hours.

<u><em>Thus, Lily spends </em></u>3\frac{1}{2}\ hours<u><em>  for babysitting which is less than 4 hours.</em></u>

Therefore, Lily babysit for less than 4 hours.

4 0
3 years ago
Find the measure of the angle, round to the nearest tenth: Sin X = .7547
dimulka [17.4K]
SIN(x) = .7547
X = INVERSE-SIN(.7547)
X = 49.0 degrees
4 0
3 years ago
What is 5/16 divided by 2/3
gayaneshka [121]
You take 5/16 division you change it in matplication 3 goes up and 2 comes down so you numbers will be
5/16 times 3/2 you take 5 time3 is 15 and 16 times 2 is 32
So ur answer will be 15/32
8 0
3 years ago
An office is divided into 8 cubicles. How many of the cubicles are carpeted if only 1/4 of the cubicles are carpeted?
djyliett [7]
U have to do it like this 1/4 and 8/100
6 0
3 years ago
Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)
DENIUS [597]

Compute the necessary values/derivatives of f(x) at x=1:

f(1)=3

f'(1)=2

f''(1)=-12

f'''(1)=-12

f^{(4)}(1)=48

f^{(5)}(1)=120

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) f(x) at x=1 by

T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5

T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5

###

Another way of doing this would be to solve for the coefficients a,b,c,d,e,g in

f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5

by expanding the right hand side and matching up terms with the same power of x.

5 0
3 years ago
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