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liq [111]
3 years ago
10

Solve the system. {y=5/6x+1 {−x+y=2

Mathematics
2 answers:
Vikentia [17]3 years ago
4 0
Y = 5/6x + 1
so we sub in 5/6x + 1 in for y in the other equation

-x + y = 2
-x + 5/6x + 1 = 2
-x + 5/6x = 2 - 1
-6/6x + 5/6x = 1
-1/6x = 1
x = 1 * -6
x = -6

-x + y = 2
-(-6) + y = 2
6 + y = 2
y = 2 - 6
y = -4

solution is (-6,-4)
astraxan [27]3 years ago
3 0
You can substitute the value of y(5/6 x + 1) from the first equation for y in the second and get -x + ( \frac{5}{6} x+1) = 2
 which becomes - \frac{1}{6} x + 1 -1=2-1
 and you get 
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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Does the table represent an exponential function? Explain.
Ede4ka [16]

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Step-by-step explanation:

We have a set of ordered pairs of the form (x, y)

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This means that:

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This is: y_2=by_1y2=by1

Now we have this set of points {(-1, -5), (0, -3), (1, -1), (2, 1)}

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\begin{gathered}\frac{y_2}{y_1}=\frac{-3}{-5}=\frac{3}{5}\\\\\frac{y_3}{y_2}=\frac{-1}{-3}=\frac{1}{3}\\\\\frac{3}{5}\neq \frac{1}{3}\end{gathered}y1y2=−5−3=53y2y3=−3−1=3153=31

Then the values of y are not multiplied by a constant amount "b"

5 0
3 years ago
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