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liq [111]
3 years ago
10

Solve the system. {y=5/6x+1 {−x+y=2

Mathematics
2 answers:
Vikentia [17]3 years ago
4 0
Y = 5/6x + 1
so we sub in 5/6x + 1 in for y in the other equation

-x + y = 2
-x + 5/6x + 1 = 2
-x + 5/6x = 2 - 1
-6/6x + 5/6x = 1
-1/6x = 1
x = 1 * -6
x = -6

-x + y = 2
-(-6) + y = 2
6 + y = 2
y = 2 - 6
y = -4

solution is (-6,-4)
astraxan [27]3 years ago
3 0
You can substitute the value of y(5/6 x + 1) from the first equation for y in the second and get -x + ( \frac{5}{6} x+1) = 2
 which becomes - \frac{1}{6} x + 1 -1=2-1
 and you get 
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Answer:

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Step-by-step exp

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37/4 ÷ 3/4

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3 0
3 years ago
10p-2(3p-6)=4(3p-6)-8p
lisabon 2012 [21]

Answer:

undefined / no solution

Step-by-step explanation:

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4 0
2 years ago
for y=x^2-10 do the following . A) Sketch a graph of the equation. B) Identify the vertex. C)Compare the graph of y=f(x) to the
Andreas93 [3]
A ) A graph of the equation is in the attachment.
B ) The vertex ( 0, -10 )
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Download docx
8 0
2 years ago
The function of g(x)=8^2-48+65 written in vertex form is g(x)= 8(x-3)^2-7 what is the vertex of g(x)
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The vertex is where g(x) = 0 
i.e. where 8(x^3)^2-7 is equal to x 

who wrote this question, there aRE OBVIOUS errors. 
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3 years ago
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