Hey here is the answer to ur question....!
Given:
AC=2
BC=2
BE=2
DE=2
DF=4
Angle DCB=angleCBE=angleBED
To find: area of the given figure
Solution: in BEDC,
Since BE=2
=>CD=2 (Opposite sides are equal in a square)
Therefore ,area of square BEDC=s*s=2*2=4 units^2
In triangle ABC,
AC=CB=2
=>area of triangle =1/2*b*h
=>area of triangle ABC=1/2*2*2
=>area of triangle =2 units^2
In triangle DEF,
DF=4
DE=2
=>area of triangle DEF=1/2*4*2
=>area of triangle DEF=4units ^2
Therefore ,area of the given figure ABEF=area of triangle ABC+area of triangle DEF+area of square BEDC
=>2+4+4
=>area of the given figure ABEF=10 units^2
Hope this helps u.........!!!!!!!