Question

Find the equation of a line that is parallel to the line y = -4× and contains the point (8,-3)

Answer 1

(Note: this is hard to explain without graphing. You might want to graph both of these lines just to make sure I did this correctly. :))

Y = -4(x) is the y = mx + b where m = slope and b = the y intercept.

So the slope of line A is -4 / 1 and the y intercept is 0. (If it's 0 there is no point in writing it down, so it was left out of the equation.)


The slope of line B with be equal to the slope of line A, so we can fill that in our equation. y = -4 x + ??

We know that y increases as x decreases.

Now we just need to scale 8, -3 down until x = 0.
 (8 - 4, -3 + 1) = (4, -2) 

(4 - 4, -2 + 1) = (0, -1)

y = -4x -1 is your final answer. Hope that helps! :)