Area of the cage : A = L * W
A = 3 * 5
A = 15 sq ft....so ur cage is 15 square ft...and they need at least 12 sq ft...so yes, it is big enough
Make it go higher the height of the roller caster will gain more potential energy than a short so go high
Answer:
The dimensions of the rectangle = 60ft by 107ft
Where 60 ft = Width of the playing field
107ft = Length of the playing field
Step-by-step explanation:
A playing field is Rectangular is shape, hence,
The formula for Perimeter of a rectangle = 2(L + W)
P = 334 ft
L = 47 + W
W = W
Hence we input these values in the formula and we have:
334 = 2(47 + W + W)
334 = 2(47 + 2W)
334 = 94 + 4W
334 - 94 = 4W
240 = 4W
W = 240/4
W = 60
There fore, the width of this playing field = 60 ft
The length of this rectangle is calculated as:
47 + W
47 + 60
= 107 ft
The length of this playing field = 107ft
Therefore the dimensions of the rectangle = 60ft by 107ft
Answer:
don't copy in a test fam dude I'm
Answer:
(-2,1),(-1,2),(-3,5/3)
Step-by-step explanation:
