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3 years ago

8

Please answershow working out please!!!!!!!!

2 answers:

Nikitich [7]3 years ago

7 0

It's as easy as I solved it

Naddik [55]3 years ago

3 0

7/10 is the answer, I know this because you have to multiply the 3/10ths by 2 and I think that's the answer I'm not responsible for any mistakes. Because clearly I said I think.

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How do you do the Pythagorean triple theory in math

Firdavs [7]

Pythagorean triples are integer solutions to the Pythagorean theorem a^2 + b^2 = c^2 I like triplets but triples seems to be the favored term for right triangle the x side is the hypotenuse the side opposite the right angle
hope this helps!

8 0

3 years ago

If an angle of 11pi/30 radian is in standard position. What is the reference angle in radian?

bixtya [17]

Answer:

$\frac{11\pi}{30}$

Step-by-step explanation:

The reference angle is an acute angle that angle in standard position makes with the positive x-axis.

The given angle in radians is

$\frac{11\pi}{30}$

This angle is already acute and hence it is itself a reference angle.

The reference angle of any angle in the first quadrant is the same angle.

4 0

3 years ago

Which is an equation of the line through the origin and (3,4)? Please help

kondor19780726 [428]

B is the answers………..

8 0

3 years ago

The prices of commodities X,Y,Z are respectively x, y, z, rupees per unit. Mr. A purchases 4 units of Z and sells 3 units of X a

liubo4ka [24]

Answer:

$(x,y,z)=(1477, 1464, 1437)$

Step-by-step explanation:

Consider the selling of the units positive earning and the purchasing of the units negative earning.

<h3>Case-1:</h3>

Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
Mr.A earns Rs6000

So, the equation would be

$3x + 5y - 4z = 6000$

<h3>Case-2:</h3>

Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
Mr B neither lose nor gain meaning he has made 0₹

hence,

$2x - 3y + z = 0$

<h3>Case-3:</h3>

Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
Mr.C earns 13000₹

therefore,

$- x + 4y + 6z = 13000$

Thus our system of equations is

$\begin{cases}3x + 5y - 4z = 6000\\2x - 3y + z = 0\\ - x + 4y + 6z = 13000\end{cases}$

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>

we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

$\begin{cases}3x + 5y - 4z = 6000\\2x - 3y + z = 0\end{cases}\\\begin{cases}2x - 3y + z = 0\\ - x + 4y + 6z = 13000\end{cases}$

Now solve the equation accordingly:

$\implies\begin{cases}11x-7y=6000\\-13x+22y=13000\end{cases}$

Solving the equation for x and y yields:

$\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}$

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

$\implies z= \dfrac{217000}{151}$

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437

6 0

2 years ago

How does solving linear inequalities compare with solving linear equations?

maks197457 [2]

It is just the difference between the signs

3 0

3 years ago