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3 years ago

Please answershow working out please!!!!!!!!

Mathematics

2 answers:

Nikitich [7]3 years ago

7 0

It's as easy as I solved it

Naddik [55]3 years ago

3 0

7/10 is the answer, I know this because you have to multiply the 3/10ths by 2 and I think that's the answer I'm not responsible for any mistakes. Because clearly I said I think.

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Need help with this math lesson

ki77a [65]

Rational numbers are numbers that can be turned into fractions. So A, C, D, E, F, G, H, and I are rational numbers

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4 years ago

Write each expression as a product of linear factors 1. X^2+1/2x 2. X^2+2x-3 3. (2x-3)^2 4. X^3+2x^2-19x-20

Grace [21]

Answer:

1. X^2+1/2x = $x(x+\frac{1}{2})$

2. X^2+2x-3 = $(x-1)(x+3)$

3. (2x-3)^2 = (2x-3)(2x-3)

4. X^3+2x^2-19x-20 = $(x+1)(x-4)(x+5)$

Step-by-step explanation:

Each expression can be written as a product of linear factors as follows

1. X^2+1/2x ⇒ $x^{2} + \frac{1}{2}x$

$x^{2} + \frac{1}{2}x$ = $x(x+\frac{1}{2})$

Hence, X^2+1/2x = $x(x+\frac{1}{2})$

2. X^2+2x-3 ⇒ $x^{2} +2x-3$

$x^{2} +2x-3 = x^{2} +3x-x-3$

$x^{2} +3x-x-3 = x(x+3) -1(x+3)$

$x(x+3) -1(x+3) = (x-1)(x+3)$

Hence, X^2+2x-3 = $(x-1)(x+3)$

3. (2x-3)^2 ⇒ $(2x-3)^{2}$

$(2x-3)^{2} = (2x-3)(2x-3)$

Hence, (2x-3)^2 = (2x-3)(2x-3)

4. X^3+2x^2-19x-20 ⇒ $x^{3}+2x^{2} -19x -20$

$x^{3}+2x^{2} -19x -20 = (x+1)(x^{2} +x-20)$

First,

$x^{2} +x-20 = x^{2} +5x-4x-20\\x^{2} +5x-4x-20= x(x+5)-4(x+5)\\x(x+5)-4(x+5) = (x-4)(x+5)$

∴ $(x+1)(x^{2} +x-20) = (x+1)(x-4)(x+5)$

Hence, X^3+2x^2-19x-20 = $(x+1)(x-4)(x+5)$

3 0

3 years ago

Discrete Math (MACM 101)

Alona [7]

I hope this helps you

n!/(n-3)!=3.n!/(n-2)!

3. (n-3)!=(n-2)(n-3)!

3=n-2

n=5

7 0

3 years ago

Distribute 5(2s^2-3s+4)

Triss [41]

10s^2-15s+20 is the answer according to distributive property

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3 years ago

Read 2 more answers

Find the value of x and y

melomori [17]

Answer:

Step-by-step explanation:

Step One: We need to find a way to equate either the x terms of the y terms in each equation. ...

Step Two: Take equation b) from equation a) to eliminate the x component. ...

Step Three: substitute the value of y into either equation to find the value of x.

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3 years ago