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bonufazy [111]
3 years ago
11

What is the slope-intercept form of them equation of a line that passes through (5, -4) and has a slope of 3/4?

Mathematics
1 answer:
EastWind [94]3 years ago
5 0

C is correct answer, passes through (5,-1) and also has slope of 3/4



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logan drov from new orland to nashvill to visit friends his speed limit is 60 miles per hour if logans driving for the trip was
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540 miles

Step-by-step explanation:

60 times 9

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The Law of Demand is one of the most famous laws in economics. It states that when the price of a good rises, the amount demande
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Falls, rises

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Which statements describe one of the transformations performed on f(x) = x^2
SashulF [63]

Answer:

The correct options are C and D

C. A translation of 5 units up

D. A reflection about the x-axis

Step-by-step explanation:

We have been given as function of the graph:

f(x) = x²

Which is transformed into the function

g(x) = -(x-2)² + 5

Consider the graph of y = x²

To convert it into the graph of given transformed function.

First reflect the graph over x-axis, the equation becomes

y = -(x)²

Then translate the graph 2 units to the right

y = -(x - 2)²

Then translate the graph 5 units up.

y = -(x - 2)² + 5

Thus, the correct statements are C and D

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3 years ago
Most US adults have social ties with a large number of people, including friends, family, co-workers, and other acquaintances. I
xxTIMURxx [149]

Answer:

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

p_v =2*P(t_{(1699)}>1.971)=0.049  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

Step-by-step explanation:

Data given and notation  

\bar X=669 represent the sample mean

s=732 represent the sample standard deviation

n=1700 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0. represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:  

Null hypothesis:\mu = 634  

Alternative hypothesis:\mu \neq 634  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(1699)}>1.971)=0.049  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

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3 years ago
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Answer:

d because it the high est

Step-by-step explanation:

be abuse it the most

8 0
3 years ago
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