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zhenek [66]
3 years ago
12

What is the midpoint of EC ?

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
7 0

<u>Given</u>:

Given that the graph OACE.

The coordinates of the vertices OACE are O(0,0), A(2m, 2n), C(2p, 2r) and E(2t, 0)

We need to determine the midpoint of EC.

<u>Midpoint of EC:</u>

The midpoint of EC can be determined using the formula,

Midpoint=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Substituting the coordinates E(2t,0) and C(2p, 2r), we get;

Midpoint=(\frac{2t+2p}{2},\frac{0+2r}{2})

Simplifying, we get;

Midpoint=(\frac{2(t+p)}{2},\frac{2r}{2})

Dividing, we get;

Midpoint=(t+p,r)

Thus, the midpoint of EC is (t + p, r)

Hence, Option A is the correct answer.

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Answer: w

Step-by-step explanation:

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3 years ago
Simplify<br><br> x^4 * x <br><br> What would be the simplified answer
kramer

Answer: The simplified answer will be: x^5

Step-by-step explanation:

x4x

=x4*x1

=(x*x*x*x)*(x)

=x*x*x*x*x

=x^5

5 0
2 years ago
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Ben has a cell phone plan that provides 200 free minutes each month for a flat rate of $39. For any minutes over 200, Ben is cha
faltersainse [42]

Answer:

\left\{\begin{matrix}39 & x\leq 200\\ 39+(x-200)\times 0.35 & x>200\end{matrix}\right.

Step-by-step explanation:

We are given that Ben has a cell phone plan that provides 200 free minutes each month for a flat rate of $39.

We are also told that For any minutes over 200, Ben is charged $0.35 per minute.

let x  be the minutes used each month

So, if x\leq 200

So, coat will be $39

If x>200

So, Ben is charged $0.35 per minute

So, when x>200

So, charge = 39+(x-200)\times 0.35

So, the piecewise functions accurately represents charges based on Ben's cell phone :

\left\{\begin{matrix}39 & x\leq 200\\ 39+(x-200)\times 0.35 & x>200\end{matrix}\right.

4 0
3 years ago
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PLEASE HELP!! SMART PEOPLE IM BEGGING! hi can you please help me, I will mark u brainliest:)
Dimas [21]
Please mark Brainliest

The answer is 17. 72

Step by step

0.02x^2 = 6.28

x^2 = 6.28 / 0.02

x^2 = 314

x= square root of 314

x = 17. 72



5 0
2 years ago
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The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?
Anit [1.1K]

Answer: The correct option is A.

Step-by-step explanation: We are given a polynomial which is a sum of other 2 polynomials.

We are given the resultant polynomial which is : 8d^5-3c^3d^2+5c^2d^3-4cd^4+9

One of the polynomial which are added up is : 2d^5-c^3d^2+8cd^4+1

Let the other polynomial be 'x'

According to the question:

8d^5-3c^3d^2+5c^2d^3-4cd^4+9=x+(2d^5-c^3d^2+8cd^4+1)

x=8d^5-3c^3d^2+5c^2d^3-4cd^4+9-(2d^5-c^3d^2+8cd^4+1)

Solving the like terms in above equation we get:

x=(8d^5-2d^5)+(-3c^3d^2+c^3d^2)+(5c^2d^3)+(-4cd^4-8cd^4)+(9-1)

x=6d^5-2c^3d^2+5c^2d^3-12cd^4+8

Hence, the correct option is A.

5 0
3 years ago
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