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3 years ago

3. Four pencils and two pens cost $0.74. Six pencils and five pens cost $1.53.

Mathematics

1 answer:

ElenaW [278]3 years ago

5 0

Answer: The cost of a pencil and a pen is 8 cents

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For the function y = 7-3x, what is ordered pair for x=5?

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(5,0) if there is no y then it is a 0

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3 years ago

4b - 7 - 15b + 3 Pls give full explanation I don't understand this stuff.

allsm [11]

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2 years ago

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HELP PLEASE! Solve for m. 3.6m = 14.4

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How many terms are in the binomial expansion of (2x 3)5? 4 5 6 7

padilas [110]

In the binomial expansion (2x + 3)^5 , there are 6 terms.

According to the question, given that

Binomial expansion (2x + 3)^5

Number of terms in a binomial expansion of (x + y)^n is

N = n + 1 words in total

In the binomial expansion (2x + 3)^5

n = 5

N = 5 + 1 = 6

Therefore, In Binomial expansion (2x + 3)^5 there are 6 terms.

The algebraic expression (x + y)n can be expanded according to the binomial theorem, which represents it as a sum of terms using separate exponents of the variables x and y. Each word in a binomial expansion has a coefficient, which is a numerical value.

The formula for expanding the exponential power of a binomial expression is provided by the binomial theorem, sometimes referred to as the binomial expansion. The following is the binomial expansion of (x + y)n using the binomial theorem:

$(x+y)^n = n_C_{0} * n_y_{0} + n_C_{1} * n-1_y_{1} + n_C_{2} * n-2_ y_{2} + ... + n_C_{n-1} * 1_y_{n-1} + n_C_{n} * 0_y_{n}$

To learn more about binomial theorem visit here : brainly.com/question/2165968

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1 year ago

When solving the equation x2 – 8x - 7 = 0 by completing the square, which equation

IgorLugansk [536]

<h3>Answer:-</h3>

Lets Solve

$\\ \rm \longmapsto \: {x}^{2} - 8x - 7 = 0 \\ \\ \rm \longmapsto \: {x}^{2} - 8 {}^{}x = 7 \\ \\ \rm \longmapsto \: 4( {x}^{2} - 8x) = 4 \times 7 \\ \\ \rm \longmapsto \: {4x}^{2} - 32x = 28 \\ \\ \rm \longmapsto \: {(2x)}^{2} - 2 \times 2x \times 8 = 28 \\ \\ \rm \longmapsto \: (2x) {}^{2} - 2 \times 2x \times 8 + {8}^{2} = 28 + {8}^{2} \\ \\ \rm \longmapsto \: {(2x - 8)}^{2} = 64 + 28 \\ \\ \rm \longmapsto \: {(2x - 8)}^{2} = 92 \\ \\ \rm \longmapsto \: 2x - 8 = \underline{ + }9.3 \\ \\ \rm \longmapsto \:2x = 8 + 9.3 \: or \: 8 - 9.3 \\ \\ \rm \longmapsto \:2x = 17.3 \:or \: - 1.3 \\ \\ \rm \longmapsto \:2x = 17.3 \\ \\ \rm \longmapsto \:x = \frac{17.3}{2} \\ \\ \rm \longmapsto x = \:8.6$

Ignore negative value

4 0

3 years ago