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2 years ago

3. Four pencils and two pens cost $0.74. Six pencils and five pens cost $1.53.

Mathematics

1 answer:

ElenaW [278]2 years ago

5 0

Answer: The cost of a pencil and a pen is 8 cents

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6+2[x+8]+3x+11+x help plzzzzz

Alex787 [66]

6+2(x+8)+3x+11+x
First you have to expand the brackets:
6+2x+16+3x+11+x
Now you group like terms (terms with the same or no variable):
2x+3x+x+11+16+6
And finally, combine like terms:
6x+33

Hope this helps :)

4 0

2 years ago

Judy has a sugar cone and wants to know how many cubic inches of ice cream it will hold if it is filled completely to the top of

Aleks [24]

Cone Volume = (π • r² • h) ÷ 3

Cone Volume = (3.14 * 1.5^2 * 4.5) / 3

Cone Volume = 10.5975 
answer is B

5 0

2 years ago

Read 2 more answers

3. Put the following numbers in order

PtichkaEL [24]

Answer:

3.85 x 10-7

8.53 x 10-5

0.00000538

3.58 x 10-6

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Farmer Jones, and his wife, Dr. Jones, decide to build a fence in their field, to keep the sheep safe. Since Dr. Jones is a math

NISA [10]

Answer: $A=\frac{14}{9}\cdot \sqrt{2}\ unit^2$

Step-by-step explanation:

Given

Two curves are given

$y=10 x^2$

and $y=x^2+2$

the two curves intersect at

$10x^2=x^2+2$

$x=\pm \frac{\sqrt{2}}{3}$

to get the we need to integrate the curves over x axis

$A=\int_{-\frac{\sqrt{2}}{3}}^{\frac{\sqrt{2}}{3}}\left ( x^2+3-10x^2\right )dx$

$A=2\int_{0}^{\frac{\sqrt{2}}{3}}\left ( 3-9x^2\right )dx$

$A=2\left [ 3\left ( \frac{\sqrt{2}}{3}\right )-\frac{9}{3}\left ( \frac{\sqrt{2}}{3}\right )^3\right ]$

$A=2\sqrt{2}\left [ 1-\frac{2}{9}\right ]$

$A=\frac{14}{9}\cdot \sqrt{2}\ unit^2$

3 0

2 years ago

The national weather service keeps records of rainfall in valleys. Records indicate that in a certain valley the annual rainfall

Setler79 [48]

Answer:

The mean is 95 and the standard deviation is 2

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Population:

Mean 95, Standard deviation 12

Samples of size 36:

By the Central Limit Theorem,

Mean 95

Standard deviation $s = \frac{12}{\sqrt{36}} = 2$

4 0

2 years ago