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Nana76 [90]
4 years ago
15

You are baking brownies for your class. There are 28 total students in your class and you have baked 23 brownies. Right and solv

e an equation to find the additional number x of Brownies you need to bake in order to have two brownies for each student. Write your equation so that the units on each side of the equation are brownies per student.
Mathematics
1 answer:
slavikrds [6]4 years ago
6 0

Answer:

x = 33

Step-by-step explanation:

Given

Students = 28

Brownies = 23

Brownies = 2\ per\ student

Required

Determine the number of brownies left

If:

Brownies = 2\ per\ student

and there are 28 students

Then:

Total\ Brownies = 2 * 28

Total\ Brownies = 56

To determine the number of brownies left, we have:

Total\ Brownies = Brownies\ Made + Brownies\ Left

56 = 23 + x

Reorder

x + 23 = 56

Collect Like Terms

x = 56 - 23

x = 33

<em>Hence, there are 33 brownies left</em>

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3 years ago
Orange M&amp;M’s: The M&amp;M’s web site says that 20% of milk chocolate M&amp;M’s are orange. Let’s assume this is true and set
SOVA2 [1]

Answer:

The correct option is (A).

Step-by-step explanation:

Let <em>X</em> = number of orange  milk chocolate M&M’s.

The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.

The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.

The event of an milk chocolate M&M being orange is independent of the other candies.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected number of orange  milk chocolate M&M’s in a bag of 55 candies as follows:

E(X)=np

         =55\times 0.20\\=11

It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.

This proportion is not surprising.

This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.

All unusual events have a very low probability, i.e. less than 0.05.

Compute the probability of P (X ≥ 14) as follows:

P(X\geq 14)=\sum\limits^{55}_{x=14}{{55\choose x}0.20^{x}(1-0.20)^{55-x}}

                 =0.1968

The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.

This probability is quite larger than 0.05.

Thus, the correct option is (A).

4 0
4 years ago
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