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Nana76 [90]
3 years ago
15

You are baking brownies for your class. There are 28 total students in your class and you have baked 23 brownies. Right and solv

e an equation to find the additional number x of Brownies you need to bake in order to have two brownies for each student. Write your equation so that the units on each side of the equation are brownies per student.
Mathematics
1 answer:
slavikrds [6]3 years ago
6 0

Answer:

x = 33

Step-by-step explanation:

Given

Students = 28

Brownies = 23

Brownies = 2\ per\ student

Required

Determine the number of brownies left

If:

Brownies = 2\ per\ student

and there are 28 students

Then:

Total\ Brownies = 2 * 28

Total\ Brownies = 56

To determine the number of brownies left, we have:

Total\ Brownies = Brownies\ Made + Brownies\ Left

56 = 23 + x

Reorder

x + 23 = 56

Collect Like Terms

x = 56 - 23

x = 33

<em>Hence, there are 33 brownies left</em>

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Answer:

11 ≤ n

Explanation:

\frac{66}{6}  = 11

More than indicates the minimum value, so you use the greater than or equal to.

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I am joyous to assist you anytime.

8 0
3 years ago
For this Prism to be a right prism, all the lateral faces must be rectangles. Is enough infromation given to prove the lateral f
Ilia_Sergeevich [38]

Answer:

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6 0
3 years ago
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strojnjashka [21]

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8 0
3 years ago
I NEED HELP ASAPP!!!​
Llana [10]

Answer:

c

Step-by-step explanation:

x - 2y = -8 \\y = 5x-2

x - 2 y = - 8

add -x to both sides

x - 2y - x = -8 - x \\- 2y = -8 - x

multiply both sides by -1/2

-2y * (\frac{-1}{2} ) = (-8-x) (\frac{-1}{2} )

y = 4 + \frac{x}{2} \\y = \frac{x}{2} + 4

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4 0
3 years ago
Let z denote a variable that has a standard normal distribution. Determine the value z* to satisfy the following conditions. (Ro
Gre4nikov [31]

Answer:

a) z* = -1.97

b) z* = -2.33

c) z* = -1.65

d) z* = 2.04

e) z* = 2.33

f) z* = -1.25.

Step-by-step explanation:

Z-score:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

a. P(z < z*) = 0.0244

We have to look at the ztable, and find z which has a pvalue of 0.0244. So it is z* = -1.97

b. P(z < z*) = 0.0098

We have to look at the ztable, and find z which has a pvalue of 0.0098. So it is z* = -2.33

c. P(z < z*) = 0.0496

We have to look at the ztable, and find z which has a pvalue of 0.0496. So it is z* = -1.65

d. P(z > z*) = 0.0204

We have to look at the ztable, and find z which has a pvalue of 1 - 0.0204 = 0.9796. So z* = 2.04

e. P(z > z*) = 0.0098

We have to look at the ztable, and find z which has a pvalue of 1 - 0.0098 = 0.9902. So z* = 2.33

(f) P(z > z* or z < -z*) = 0.201

This is z which has a pvalue of 0.201/2 = 0.1055. So it is z* = -1.25.

4 0
3 years ago
Read 2 more answers
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