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AlexFokin [52]
3 years ago
14

Vertical angles are congruent a. never b. sometimes c. always

Mathematics
1 answer:
yarga [219]3 years ago
5 0

Answer:

C

Step-by-step explanation:

because vertical angles angles that are opposite each other and formed by two intersecting lines are congruent

hope this helps :D

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Makovka662 [10]

Let u=x^2-4 and v=4x-5. By the product rule,

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}

and we have

\dfrac{\mathrm du}{\mathrm dx}=2x

\dfrac{\mathrm dv}{\mathrm dx}=4

So we end up with

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

Replace u,v to get everything in terms of x:

\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3

We can simplify this by factoring:

10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)

=2(x^2-4)^4(4x-5)^3(28x^2-57)

7 0
3 years ago
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cestrela7 [59]

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c)  With 36 oz of seasoning...we can cook      36 / 2.4  =  15 lbs of crawfish

7 0
3 years ago
Given f(x) = 3 and g(x) = 5x + 7, find (f + g)(-8).
levacccp [35]

Answer:

-30

Step-by-step explanation:

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g(x) = 5x + 7, so g(-8) = 5(-8) + 7 = -33

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This is the sum of two functions both evaluated at x = -8.

4 0
3 years ago
An equation that involves a multiplication addition, contains a variable, and has a solution of 8.
yulyashka [42]
A variable is an unknown like x so 

first we start with 
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then we divide ( because you must multiply to reverse division)
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find x
7 0
3 years ago
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