Check the picture below, notice those three quadrilaterals, bearing in mind that a square and rhombus both have equal sides all around.
Find the simple interest on $6000 from 16 May 2010 to 9 October 2010 at 10 percent per annum
1 answer:
Answer:
$240.02
Step-by-step explanation:
10% per year means "how much percent per day?"
We need to divide 10 by 365 since there are 365 days in a year. Hence,
So, that is 0.0274% per day
In decimal, we have to divide this percentage by 100, so, that is:
0.0274/100 = 0.000274
Daily interest on the principal is thus the multiplication of this value with principal (6000), that is:
0.000274 * 6000 = 1.644
<u>For how many days??</u>
From 16 May till 9 October would be:
16 May - 31 May = 15 days
1 June - 30 June = 30 days
1 July - 31 July = 31 days
1 Aug - 31 Aug = 31 days
1 Sep - 30 Sep = 30 days
1 Oct - 9 Oct = 9 days
Total Days is 15 + 30 + 31 + 31 + 30 + 9 = 146 days
Thus, total simple interest for 146 days would be:
1.644 * 147 = $240.02
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Answer:
12.7m
Step-by-step explanation:
The equation for motion to be used to find how far the water travels is
xf = xi + Vix(t) + 1/2axt^2
xf = 0 + ViCos α(t) + 0
xf = ViCosα(t)
xf = 12 Cos 30°(t)
xf = (6√3)t
To find the total times we will use the vertical displacement equation
yf = yi + Viy(t) + 1/2ayt^2
0 = 0 + ViSinα(t) + (1/2 * (-9.8)t^2)
0 = 12Sin30°(t) - 4.9t^2
4.9t^2 = 12Sin30°(t)
4.9t^2 = 6t
Divide through by t
4.9t = 6
t = 6/4.9
t = 1.22secs
Put t = 1.22 into (6√3)t
xf = 6√3 * 1.22
xf = 12.7m
