This is an awful question. They mean to say the number of hours practicing <em>per week</em> (we'll call it h) varies inversely with the <em>time</em> (t) she runs her event. Unless they mean to imply more practicing makes Tyler slower, in which case she should just get a pizza.
Inverse variation means the product is a constant, we'll call it k.
ht = k
When h = 1 hour t=6 minutes
(1)(6) = k
k = 6 (hour*minutes, but as long as we're consistent we don't need to sweat the unit.)
Decreasing her time by one minute means t = 6 - 1 = 5. We solve for h.
ht = k
h = k/t = 6/5 = 1.2 hours
Answer: 1.2 hours, second choice
We can use the difference of two squares, which is:
x^2 + y^2 = (x-y)(x+y)
So,
(9m-7)(9m+7)
Hope this helps!
Answer:
C 16
Step-by-step explanation:
Using ratios
3:12
12/3=4
4:x
4*4=16
x=16
4:16
hope this helps:)
18 and 35. The numbers whose sum 53 are 18 and 35.
The key to solve this problem is using a system of equations.
There are two numbers whose sum is 53. This number can be represented as x and y. So:
x + y = 53
Three times the smaller number is equal to 19 more than the larger. Let's set x as the smaller number and y the larger number. So:
3x = 19 + y
Clear y in both equations and let's use the equalization method to solve for x:
y = 53 - x and y = 3x - 19
Then,
53 - x = 3x - 19
53 + 19 = 3x + x ---------> 3x + x = 53 + 19 -------> 4x = 72
x = 72/4 = 18
To find y, let's substitute x = 18 in the equation x + y = 53
18 + y = 53 --------> y = 53 - 18
y = 35
