Answer:
The answer to your question is the first option
Step-by-step explanation:
64
Process
1.- Find the prime factors of 64
64 2
32 2
16 2
8 2
4 2
2 2
1
64 = 2⁶
2.- Express 64 as a fractional exponent
64
3.- Simplify
64
64
64![^{1/4} = 2\sqrt[4]{2^{2}}](https://tex.z-dn.net/?f=%5E%7B1%2F4%7D%20%3D%202%5Csqrt%5B4%5D%7B2%5E%7B2%7D%7D)
4.- Result
64![^{1/4} = 2\sqrt[4]{4}](https://tex.z-dn.net/?f=%5E%7B1%2F4%7D%20%3D%202%5Csqrt%5B4%5D%7B4%7D)
First, you need to rewrite the expression into binomial form, so you are working with two terms (as you world with a quadratic):
(x²)²-3(x²)-4=0
Now, you can place the x²s into brackets as the coefficient is now 1:
(x² )(x² )
Next, find out two numbers that add together to give you -3 and multiply to give -4 (these are the leftover integers after removing the x²s). These two numbers are -4 and 1.
Place the -4 and 1 into the brackets:
(x²-4)(x²+1)=0
Notice that the x²-4 is a difference of two squares, so can be further factorised into (x+2)(x-2)
This leaves you with a final factorisation of:
(x+2)(x-2)(x²+1)=0
Now we handle each bracket individually to obtain our four solutions for x:
x+2=0
x=-2
x-2=0
x=2
x²+1=0
x²=1
x=<span>±1</span>
-18+54
-17+53
-16+52
-15+51
-14+50
-13+49
-12+48
-11+47
-10+46
-9+45
-8+44
-7+43
-6+42
-5+41
-4+40
-3+39
-2+38
-1+37
1+35
2+34
3+33
4+32
5+31
6+30
7+29
8+28
9+27
10+26
11+25
12+24
13+23
14+22
15+21
16+20
17+19
18+18
(2,0)
the first # is the x coordinate which is left and right. Since B is 2 to the right from the center (0,0) x is 2. Left would make it negative
The second # is the y coordinate which is up and down. Since B is on the x axis the y coordinate is 0.
