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IrinaK [193]
3 years ago
15

Please help me out with question 2

Mathematics
1 answer:
Colt1911 [192]3 years ago
6 0

n = 8

the sum to n terms of a geometric sequence is

S_{n} = \frac{a(1-r^{n )} }{1-r}

where a is the first term and r the common ratio

here a = 16 and r = \frac{64}{-32} = \frac{-32}{16} = - 2

S_{n} = ( 16( 1 - ( - 2 )^n )/1 - (- 2 )) = - 1360

\frac{16}{3} ( 1 - (- 2 )^n ) = - 1360

multiply both sides by \frac{3}{16}

1 - (- 2 )^n = - 255

- (- 2 )^n = - 256

)-2)^n = 256

note that 2^{8} and (-2)^{8} = 256

hence n = 8



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