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Leto [7]
4 years ago
6

What is the minimum value of the function g(x) = x2 - 6x – 12? -21 3-21 3 3+21

Mathematics
1 answer:
balandron [24]4 years ago
4 0

Answer:

- 21

Step-by-step explanation:

The minimum value occurs at the vertex of the function

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

To obtain this form use the method of completing the square

Given

f(x) = x² - 6x - 12

add/ subtract ( half the coefficient of the x- term)² to x² - 6x

f(x) = x² + 2(- 3)x + 9 - 9 - 12

     = (x - 3)² - 21

with vertex = (3, - 21 )

The minimum is the value of k, that is minimum value = - 21

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A company has a cost equation of c=0.925x^2-4x+20 and a profit equation of p=-1.125x^2+6x+40. Solve for the breakeven point.
lana66690 [7]
0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40 (at break even point)

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3 0
3 years ago
Find the value of x in log^x base 9=3÷2​
Luba_88 [7]

Answer:

x = 27.

Step-by-step explanation:

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3 years ago
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6 0
4 years ago
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Kobotan [32]
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Explanation:
5 0
3 years ago
Let f(x) = 9x − 2 and g(x) = −x + 3. Find f(g(x)). (1 point)
postnew [5]
In looking for f(g(x)), one has to substitute the expression of g(x) in place of the variable "x" in f(x). This is shown below:

Given:

f(x) = 9x - 2
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f(g(x)) = 9(-x + 3) - 2
f<span>(g(x)) = -9x + 27 - 2
</span>f<span>(g(x)) = -9x + 25</span>
6 0
3 years ago
Read 2 more answers
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