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Marianna [84]
3 years ago
8

Help, I’m stuck. Thank you very much

Mathematics
1 answer:
ZanzabumX [31]3 years ago
5 0
If you notice, the container is really just two circles, with a diameter of 4 each, and a square with sides of 10.5.

now, if we just get the area of each circle, keeping in mind their radius is half of the diameter, namely r = 2, and get the area of the 10.5x10.5 square, sum them up, that'd be the surface area of the container.

\bf \stackrel{\textit{2 circle's area}}{2(\pi r^2)}~~+~~\stackrel{\textit{area of the square}}{10.5\cdot 10.5}
\\\\\\
\stackrel{\textit{2 circle's area}}{2(\pi 2^2)}~~+~~\stackrel{\textit{area of the square}}{10.5\cdot 10.5}\implies 8\pi + 110.25
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<h2>Translating Word Equations into Numerical Equations</h2>

To change words into equations, we can recognize keywords that translate into operations and/or numbers:

  • <em>quotient</em> = divide
  • <em>a number/the number/two numbers</em> = variables
  • <em>sum</em> = add

<h2>Solving the Question</h2>

Let the two numbers be <em>a</em> and <em>b</em>.

We're given:

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  • sum of <em>a</em> and <em>b</em> is 8
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First, isolate <em>a</em> in the first equation and substitute it in the second equation to solve for <em>b</em>:

\dfrac{a}{b}=3\\\\a=3b

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Therefore, one of the numbers is 2. Substitute this into one of our equations to solve for <em>a</em>:

a+b=8\\a+2=8\\a=6

Therefore, the other number is 6.

<h2>Answer</h2>

The two numbers are 2 and 6.

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