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natali 33 [55]
3 years ago
8

Which situation can be represented by the inequality?

Mathematics
2 answers:
kherson [118]3 years ago
3 0
B. Junichi's garden is wider than 50 ft.
astra-53 [7]3 years ago
3 0

Answer:

B. Junichi's garden is wider than 50 ft.

Step-by-step explanation:

I took the test online in K12 and when I reviewed it said that B is the correct answer.

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A ripe pear falls from a tree and lands on the ground. As it hit the ground, the pear had a speed of 34 feet per second. Approxi
borishaifa [10]
The potential energy is converted into kinetic energy.
 Therefore, for conservation of energy we have:
 mgh = (1/2) m * v ^ 2
 From here we clear the speed:
 v = root (2 * g * h)
 The height will then be:
 h = v ^ 2 / (2 * g)
 Substituting the values:
 h = (34) ^ 2 / (2 * (32))
 h = 18.0625 feet
 Answer: The pear before it fell was 18.0625 feet up in the tree.
4 0
3 years ago
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a table that originally cost $196 is on sale for $160.00. What is the percent of decrease, rounded to the nearest tenth?
AfilCa [17]
Hmmm.. I solved it and got 82%. I may be wrong, but try it out. 
8 0
3 years ago
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Helo me i will help you back thanks ut due this period and im freaking out...
UNO [17]

Answer:

6 to 2

is pigs to laces


4 0
3 years ago
Find the absolute maximum and absolute minimum values of f on the given interval.
anyanavicka [17]

The question is missing parts. Here is the complete question.

Find the absolute maximum and absolute minimum values of f on the given interval.

f(x)=xe^{-\frac{x^{2}}{32} } , [ -2,8]

Answer: Absolute maximum: f(4) = 2.42;

              Absolute minimum: f(-2) = -1.76;

Step-by-step explanation: Some functions have absolute extrema: maxima and/or minima.

<u>Absolute</u> <u>maximum</u> is a point where the function has its greatest possible value.

<u>Absolute</u> <u>minimum</u> is a point where the function has its least possible value.

The method for finding absolute extrema points is

1) Derivate the function;

2) Find the values of x that makes f'(x) = 0;

3) Using the interval boundary values and the x found above, determine the function value of each of those points;

4) The highest value is maximum, while the lowest value is minimum;

For the function given, absolute maximum and minimum points are:

f(x)=xe^{-\frac{x^{2}}{32} }

Using the product rule, first derivative will be:

f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )

f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} ) = 0

1-\frac{x^{2}}{16}=0

\frac{x^{2}}{16}=1

x^{2}=16

x = ±4

x can't be -4 because it is not in the interval [-2,8].

f(-2)=-2e^{-\frac{(-2)^{2}}{32} }=-1.76

f(4)=4e^{-\frac{4^{2}}{32} }=2.42

f(8)=8e^{-\frac{8^{2}}{32} }=1.08

Analysing each f(x), we noted when x = -2, f(-2) is minimum and when x = 4, f(4) is maximum.

Therefore, absolute maximum is f(4) = 2.42 and

absolute minimum is f(-2) = -1.76

8 0
3 years ago
NEED HELP ON 3 AND 6 PLEASE
den301095 [7]
You didn’t even put 3 on the pic so I can’t help
8 0
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