How do you calculate the residuals of a scatter plot?

1 answer:

6 0

Hello

A residual<span> is the difference between the observed y-value (from </span>scatter plot<span>) and the predicted y-value (from regression </span>equation<span> line). It is the vertical distance from the actual </span>plotted<span> point to the point on the regression line.
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Have a nice day kid!

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Evaluate the following expressions if a = 2, b = 3, x = 4, and y = 5.<br> b^2+3(2x-y)

butalik [34]

Hi there! Hopefully this helps!

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<h2 /><h2>Answer: 18</h2><h2>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</h2><h2 />

First we need to substitute the value of the variable into the expression.

$b^{2}+3(2x-y)$ = $3^{2} + 3 (2(4)-5)$ .

Now we need to solve $3^{2} + 3 (2(4)-5)$ .

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$3^{2} + 3 (2(4)-5)$

First, calculate 3 to the power of 2 and get 9.

$9+3(2\times 4-5)=18$

Multiply 2 and 4 to get 8.

$9+3(8-5) =18$

Subtract 5 from 8 to get 3.

$9+3\times 3 =18$

Multiply 3 and 3 to get 9.

$9+9 =18$ .

<h2>And the answer is, you guessed it, 18!</h2>

7 0

2 years ago

A chemical company makes two brands of antifreeze. The first brand is 20% pure antifreeze, and the second brand is 70% pure anti

andre [41]

Answer:

First brand of antifreeze: 21 gallons

Second brand of antifreeze: 9 gallons

Step-by-step explanation:

Let's call A the amount of first brand of antifreeze. 20% pure antifreeze

Let's call B the amount of second brand of antifreeze. 70% pure antifreeze

The resulting mixture should have 35% pure antifreeze, and 30 gallons.

Then we know that the total amount of mixture will be:

$A + B = 30$

Then the total amount of pure antifreeze in the mixture will be:

$0.2A + 0.7B = 0.35 * 30$

$0.2A + 0.7B = 10.5$

Then we have two equations and two unknowns so we solve the system of equations. Multiply the first equation by -0.7 and add it to the second equation:

$-0.7A -0.7B = -0.7*30$