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Ksju [112]
3 years ago
8

How many solutions can be found for the equation 4x − 8 − 4x = 9?

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
5 0
I hope this helps you



4x-8-4x=9

0=9+8

0=17


no solution
ipn [44]3 years ago
5 0

Answer:

No solution

Step-by-step explanation:

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Can someone help me with this?
Alexeev081 [22]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the areas,

Area of a rectangle = length * width.

hence, l = 11 and w = 4

hence, 4*11 = 44 square units.

Area = 44 sq. units

8 0
3 years ago
Solve (9x-4)^2=18 using the square root method
Damm [24]

Answer:

x = 4/9 + sqrt(2)/3 or x = 4/9 - sqrt(2)/3

Step-by-step explanation:

Solve for x over the real numbers:

(9 x - 4)^2 = 18

Take the square root of both sides:

9 x - 4 = 3 sqrt(2) or 9 x - 4 = -3 sqrt(2)

Add 4 to both sides:

9 x = 4 + 3 sqrt(2) or 9 x - 4 = -3 sqrt(2)

Divide both sides by 9:

x = 4/9 + sqrt(2)/3 or 9 x - 4 = -3 sqrt(2)

Add 4 to both sides:

x = 4/9 + sqrt(2)/3 or 9 x = 4 - 3 sqrt(2)

Divide both sides by 9:

Answer: x = 4/9 + sqrt(2)/3 or x = 4/9 - sqrt(2)/3

7 0
3 years ago
10.) This week, you worked shifts that were 6 hours, 5 hours,
dimaraw [331]

Answer:

The average would be 22.25

Step-by-step explanation:

Average = \frac{sum}{count }

6+5+74+4= 89

there are four numbers

\frac{89}{4}=22.25

<h3> </h3>
7 0
3 years ago
Find the value of tan theta if sin theta = 12/13 and theta is in quadrant 2
nadya68 [22]

In quadrant 2, \sin\theta>0 and \cos\theta. Use the Pythagorean identity to establish that

\sin^2\theta+\cos^2\theta=1\implies\cos\theta=-\sqrt{1-\sin^2\theta}=-\dfrac5{13}

Then

\tan\theta=\dfrac{\sin\theta}{\cos\theta}=\dfrac{\frac{12}{13}}{-\frac5{13}}=-\dfrac{12}5

7 0
3 years ago
Solve the quadratic equation by completing the square.<br><br> 3x2 - 6x - 4 = 0
Akimi4 [234]

Answer:

-0.53, 2.53 to the nearest hundredth.

Step-by-step explanation:

3x^2 - 6x - 4 = 0    

3(x^2 - 2) - 4 = 0

3 [ ( x - 1)^2 - 1] = 4

3(x - 1)^2 - 3 = 4

3(x - 1)^2 = 7

(x - 1)^1 = 7/3

x - 1 = +/- √(7/3)

x =   +/- √(7/3) + 1

x = 2.53, -0.53.

7 0
3 years ago
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