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Tcecarenko [31]
3 years ago
15

how for is Blaine's house if you must drive 6.5 hours through the woods at an average of 45mph to get there?

Mathematics
1 answer:
omeli [17]3 years ago
3 0
Six and a half hours at a speed of 45 mph. 45 mph is forty five miles per hour. since there are six full hours, multiply six (time) by speed (45) to get the distance within the six full hours, which is 270 miles. you also have an additional half hour at a 45 mph speed, so rather than going 45 miles in one hour, you for half an hour, meaning you go 22.5 miles. add these two together (270 + 22.5) to get 292.5 miles. a faster way to get to this would be to multiply 6.5 * 45. hole this helps!
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We're looking for a solution of the form F(x,y)=C. By the chain rule, this solution should have total differential

\mathrm dF=\dfrac{\partial F}{\partial x}\,\mathrm dx+\dfrac{\partial F}{\partial y}\,\mathrm dy=0

and the equation is exact if the mixed second-order partial derivatives of Fare equal, i.e. \frac{\partial^2F}{\partial x\partial y}=\dfrac{\partial^2F}{\partial y\partial x}.

The given ODE is exact, since

\dfrac{\partial(2xy^3+\cos x)}{\partial y}=6xy^2

\dfrac{\partial(3x^2y^2-\sin y)}{\partial x}=6xy^2

Then

\dfrac{\partial F}{\partial x}=2xy^3+\cos x\implies F(x,y)=x^2y^3+\sin x+f(y)

\dfrac{\partial F}{\partial y}=3x^2y^2-\sin y=3x^2y^2+\dfrac{\mathrm df}{\mathrm dy}

\dfrac{\mathrm df}{\mathrm dy}=-\sin y\implies f(y)=\cos y+C

\implies x^2y^3+\sin x+\cos y=C

With y(0)=\pi, we get

\cos\pi=C\implies C=-1

\implies\boxed{x^2y^3+\sin x+\cos y=-1}

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