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Bas_tet [7]
2 years ago
12

Milliliters in one liter

Mathematics
1 answer:
aev [14]2 years ago
5 0
There are 1,000,000 milliliters in one liter
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What is the solution to this equation?
kirill [66]
The correct answer for the problem above is -23 .

Explanation

1. collect the like terms

2x + x - 11 + 3 - 7x = 15
2x , x , & -7x are like terms
-11 & 3 are like terms

2x + x -7x = -4x
-11 + 3 = -8

2. Move constant to the right-hand side and change its sign .

-4x = 15 + 8
-4x = 23

3. Make the signs on both sides of the equation

-4x = 23 turning into 4x = -23

answer =

4x = -23



7 0
3 years ago
On the first day, you pay $5 for 2 boxes of popcorn.
ahrayia [7]

Answer:

10 5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Can you use doubling for 7 times 3
V125BC [204]
What do you mean doubling? You can add 7+7+7 which equals 21. 
4 0
3 years ago
Read 2 more answers
Please help me with this question!
gavmur [86]
First off, let's convert the percentages to decimal format, so our 77% turns to 77/100 or 0.77, and our 55% turns to 55/100 or 0.55 and so on

now, the sum of both salines, must add up to the 77% mixture, let's say is "y"
so, 11 + 4 = y, and whatever the concentration level is, must also sum up to the mixture's concentration of 77%

anyway   thus

\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{first sol'n}&11&x&11x\\
\textit{second sol'n}&4&0.55&2.20\\
------&-----&-------&-------\\
mixture&y&0.77&0.77y
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
11+4=y\implies 15=\boxed{y}\\
11x+2.2=0.77y\\
----------\\
11x+2.2=0.77\cdot \boxed{15}
\end{cases}

solve for "x"
6 0
3 years ago
I need help with This question please
shepuryov [24]
3173.40 x 3 = 9520.20
4 0
3 years ago
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