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Bas_tet [7]
3 years ago
12

Milliliters in one liter

Mathematics
1 answer:
aev [14]3 years ago
5 0
There are 1,000,000 milliliters in one liter
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If you roll a single six-sided die, what is the probability of rolling an odd number? A. 1/6 B. 1/3 C. 1/2 D. 3
Leviafan [203]

Answer:

1/2

Step-by-step explanation:

there are exactly 50-50 chances of you rolling an odd since the die goes up to 6. there are 3 odd numbers in a 6-sided die, that over 6 is equal to 1/2.

3 0
3 years ago
What is the calculation for 15-(0.7×3)
vesna_86 [32]
The answer is 12.9
()=1st 
0.7x3=2.1
2.1-15=
12.9
5 0
4 years ago
Read 2 more answers
HELP PLZ!!!!
Llana [10]

Answer:

Step-by-step explanation:

Team A : the mean height (average) is :

(75 + 64 + 78 + 65 + 68) / 5 = 350/5 = 70 inches

the range is highest number minus lowest number ...78 - 64 = 14

Team B : the mean height (average) is :

(76 + 68 + 70 + 74 + 67) / 5 = 355/5 = 71 inches

the range is : 76 - 67 = 9

===========================================================

A). nope....it mentions nothing of the weight

B) nope....mean height of team A is not greater

C) nope...because that 75 inch player on team A

D) THIS ONE....the range for team A is greater then the range for team B

3 0
3 years ago
Y
Vitek1552 [10]

Answer:

x = 9

Step-by-step explanation:

See the attachment for step-by-step

5 0
2 years ago
I just need help cause if I don’t I don’t know what imma do
erica [24]

Answer:

P(32) = \frac{1}{90}

P(Odd) = \frac{1}{2}

P(Multiples\ 5) = \frac{1}{5}

Step-by-step explanation:

Given

Sample Space = 10 to 99

First, we calculate the sample size (n)

n = 99 - 10 + 1

n = 90

Solving (a): P(32)

In 10 to 99, there is only 1 32.

So,

P(32) = \frac{n(32)}{n}

P(32) = \frac{1}{90}

Solving (b): P(Odd)

There are 45 odd numbers between 10 and 99

i.e.

n(Odd)  = 45

So:

P(Odd) = \frac{n(Odd)}{n}

P(Odd) = \frac{45}{90}

P(Odd) = \frac{1}{2}

Solving (c): P(Multiple of 5)

There are 18 multiples of 5 between 10 and 99

i.e

P(Multiples\ 5) = \frac{18}{90}

P(Multiples\ 5) = \frac{1}{5}

4 0
3 years ago
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