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3 years ago

What is the calculation for 15-(0.7×3)

Mathematics

2 answers:

vesna_86 [32]3 years ago

5 0

The answer is 12.9
()=1st
0.7x3=2.1
2.1-15=
12.9

rodikova [14]3 years ago

5 0

PEMDAS

15 - (0.7*3)

0.7 * 3 = 2.1

15 - 2.1 = 12.9

Answer: 12.9

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At the movie theatre, child admission is $6.30 and adult admission is $9.90 . On Monday, 159 tickets were sold for a total sales

frez [133]

C = child tickets
a = adult tickets

Solve this with the substitution method.
Make two equations:

6.30c + 9.90a = 1,246.50
c + a = 159

Solve for c.
Subtract 9.90a from both sides.

6.30c = 1,246.50 - 9.90a
Divide both sides by 6.30.

c = 197.86 - 1.57a (rounded to hundredths)
Plug c into second equation.

197.86 - 1.57a + a = 159
Combine like terms.

197.86 - 0.57a = 159
Subtract 197.86 from both sides.

-0.57a = -38.86
Divide both sides by -0.57.

a = 68.18
round up to ones: 68

 $\boxed {68~adult~tickets}$ were sold.

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3 years ago

Rogers’s car loan is automatically deducting $35 from his bank account every month. How much will the deductions total for the y

MrRa [10]

Well since there is 12 months in a year you would multiply 35 by 12, so the answer is 420

4 0

3 years ago

Underage drinking, Part I: Data collected by the Substance Abuse and Mental Health Services Administration (SAMSHA) suggests tha

dezoksy [38]

Answer:

a. Yes, there are 10 independent trials, each with exactly two possible outcomes, and a constant probability associated with each possible outcome.

b. The probability is 0.2029 or 20.29%

c. The probability is 0.2029 or 20.29%

d. The probability is 0.1671 or 16.71%

e. The probability is 0.9975 or 99.75%

Step-by-step explanation:

a. Yes, there are 10 independent trials, each with exactly two possible outcomes, and a constant probability associated with each possible outcome.

b. Let's use the binomial distribution table, this way:

Binomial distribution (n=10, p=0.697)

f(x) F(x) 1 - F(x)

x Pr[X = x] Pr[X ≤ x]

0 0.0000 0.0000

1 0.0002 0.0002

2 0.0016 0.0017

3 0.0095 0.0112

4 0.0384 0.0496

5 0.1059 0.1555

6 0.2029 0.3584

7 0.2668 0.6252

8 0.2301 0.8553

9 0.1176 0.9729

10 0.0271 1.0000

The probability is 0.2029 or 20.29%

c. If 69.7% of 18-20 years old consumed alcoholic beverages in 2008, therefore, 30.3% did not and the binomial distribution table is:

Binomial distribution (n=10, p=0.303)

f(x) F(x) 1 - F(x)

x Pr[X = x] Pr[X ≤ x]

0 0.0271 0.0271

1 0.1176 0.1447

2 0.2301 0.3748

3 0.2668 0.6416

4 0.2029 0.8445

5 0.1059 0.9504

6 0.0384 0.9888

7 0.0095 0.9983

8 0.0016 0.9998

9 0.0002 1.0000

10 0.0000 1.0000

The probability is 0.2029 or 20.29%

d. Let's use the binomial distribution table, this way:

Binomial distribution (n=5, p=0.697)

f(x) F(x) 1 - F(x)

x Pr[X = x] Pr[X ≤ x]

0 0.0026 0.0026

1 0.0294 0.0319

2 0.1351 0.1671

3 0.3109 0.4779

4 0.3576 0.8355

5 0.1645 1.0000

P(0) + P(1) + P (2) = 0.0026 + 0.0294 + 0.1351

The probability is 0.1671 or 16.71%

e. Using the same binomial distribution table we used in d. we have:

P(1) + P (2) + P(3) + P(4) + P (5) = 0.0294 + 0.1351 + 0.3109 + 0.3576 + 0.1645

The probability is 0.9975 or 99.75%

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3 years ago

Simplify 3(tan^2 theta - sec^2 theta)

Nesterboy [21]

Answer:

sin ^2(x)

Step-by-step explanation:

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What is an equation of the line that passes through the points (−7,−7) and (−5,−3)?

Lana71 [14]

The answers is -10/13

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