Using the information given above, the sampling distribution of the sample proportion of 100-ohm gold-band is 2.
- <em>Sampling distribution of proportion, P = 2% = 0.02 </em>
- <em>Sample size, n = 100</em>
<u>The sampling distribution of the sample proportion can be calculated thus</u>:
- <em>Distribution of sample proportion = np</em>
Distribution of sample proportion = (100 × 0.02) = 2
Therefore, there is a probability that only 2 of the samples will have resistances exceeding 105 ohms.
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Answer:
t = 6/5
Step-by-step explanation:
Step 1: Define
k(t) = 10t - 19
k(t) = -7
Step 2: Substitute and Evaluate
-7 = 10t - 19
12 = 10t
t = 6/5
Answer:
5%
Step-by-step explanation:
you know 10% of 60 is 6. 3 is half of 6, and 5% is half of 10.
hope this helped!
Let
be the number of rides Chandler takes in a month. Then the cost with the MetroCard is still $81, but the cost without the MetroCard is
. So we can set up an equation representing what we want: "The cost with a MetroCard of r rides in a month is less than the cost without a MetroCard." In equations,
Thus, at a minimum, Chandler must take 41 rides for his MetroCard to be cheaper than not having it.
Answer:
ok so we need to find the percent so
8.46 divided by 42.3=0.2
she she tipped 20%
Hope This Helps!!!
